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krek1111 [17]
3 years ago
14

A standard inverting op-amp circuit has an R1 of 10 kΩ and an Rf of 220 kΩ. If the offset current is 100 nA the output offset vo

ltage due to this current is ________.
Physics
1 answer:
kiruha [24]3 years ago
6 0

Answer:

The value is  V_{os} = 0.001 \  V

Explanation:

From the question we are told that

     The circuit resistance is  R_1 =  10 \ k \Omega

     The feedback resistance  is  R_f =  220 \ k \Omega

      The offset current is  I_{os } = 100 \  nA  =  100 * 1)^{-9} \ A

Generally the offset voltage is mathematically reparented as

           V_{os} =  R_f * I_{os}

=>        V_{os} = 10 *10^{3}*  100 *10^{-9}

=>        V_{os} = 0.001 \  V

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Mice21 [21]

The type of friction of a kite suspended in the sky that is flowing back and forth is fluid friction. The fluid here is the air that helps the kite move back and forth. The kite feels a drag force due to air which acts in the upward direction.

5 0
3 years ago
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Pedro e Maria saíram para passear de carro. Eles partiram de São Paulo às 10 h em direção à Braúna, localizada a 500 km da capit
Salsk061 [2.6K]

Answer:

This can be translated to:

"P edro and Maria went for a drive. They left São Paulo at 10 am towards Braúna, located 500 km from the capital. As the journey was long, they made two 15-minute stops for gas and also spent 45 minutes for lunch. When arriving at the final destination, Maria looked at the clock and saw that it was 6 pm. What is the average speed of the trip?"

Ok, the first thing we know is, that for the average speed we can write:

Speed = Distance/time.

First, we know that Distance = 500km.

And for the time we have two possiblities:

The total average speed will decrease because they were stopped a total of:

15min + 15min + 45min = 75min = 1.25 hours

Then if the travel starts at 10am, and ends at 6 pm, the total time that has passed is:

6pm = 18hs

6pm - 10am = 18 - 10 = 8hs

Then the average speed will be:

Speed = 500km/8h = 62.5 km/h.

Now, if we considerate the average speed only when they are moving, the total time that they are moving is:

Total time in travel - time that they where stopped

8h - 1.25h = 6.75h

Then the average speed would be:

Speed = 500km/6.75h = 74.1 km/h

4 0
3 years ago
A car travelling at 32 m/s decelerates at a rate of 6 m/s ^ 2 over 4 secondsWhat is the final velocity the car
Pachacha [2.7K]

Answer:

v=8m/s

Explanation

The initial velocity, u, of the car=32m/s

Since the car has decelerated, we negate the acceleration

This implies that,

a=-6m{s}^{ -2}

Time,t=4s

Let v be the final velocity,

using the relation,

a =  \frac{v - u}{t}

We obtain the below by substitution

- 6= \frac{v - 32}{4}

By cross multiplying we obtain,

- 6 \times 4 = v - 32

- 24=v-32

- 24+32=v

v=8m/s

5 0
3 years ago
If a car is moving with a speed of 5 km/h on a highway. Find the distance travelled by the car in 2 hours?.​
grin007 [14]

Answer:

Distance = 10 kilometers.

Explanation:

Given the following data;

Speed = 5km/h

Time = 2 hours

To find the distance traveled;

Distance = speed * time

Distance = 5 * 2

Distance = 10 kilometers

Therefore, the distance travelled by the car is 10 kilometers.

5 0
2 years ago
A boat is headed with a velocity of 18 meters/second toward the west with respect to the water in a river. If the river is flowi
artcher [175]

Answer:

20.5

Explanation:

in this case, the two vectors are in the same direction, so they simply add:

total motion = 18m/s + 2.5m/s = 20.5m/s to the west

8 0
3 years ago
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