Answer:
Tension in the string is equal to 58.33 N ( this will be the strength of the string )
Explanation:
We have given mass m = 1.7 kg
radius of the circle r = 0.48 m
Kinetic energy is given 14 J
Kinetic energy is equal to
So
v = 4.05 m/sec
Centripetal force is equal to
So tension in the string will be equal to 58.33 N ( this will be the strength of the string )
The complete question is: A student draws a picture of the products and reactants of a chemical reaction. What, if anything, is wrong with the drawing?
A) The drawing is wrong because there are more chemicals on the products side.
B) The drawing is correct because there are 12 compounds on each side of the arrow.
C) The drawing is wrong because there are different compounds on each side of the arrow.
D) The drawing is correct because there are 12 atoms of each type on each side of the arrow.
Answer:
Option D is correct
Explanation:
In the diagram attached below, it can be seen that there are 12 atoms of element which combine with 12 atoms of another element forming a compound. For the drawing to be correct, there should be 12 atoms of each type of element on both the reactants as well as product side, which is the case. There cannot be imbalance in the number of atoms of different elements on the two sides for a chemical reaction to occur.
Hence, option D is correct.
Answer:
Explanation:
It is given that,
Initially, the electron is in n = 7 energy level. When it relaxes to a lower energy level, emitting light of 397 nm. We need to find the value of n for the level to which the electron relaxed. It can be calculate using the formula as :
R = Rydberg constant,
Solving above equation we get the value of final n is,
or
So, it will relax in the n = 2. Hence, this is the required solution.
Answer:
i) No, the spring scale does not read a different value
ii) The torque will read a different value, it will reduce
iii) The spring scale does not need to be measured at the center of mass location.
Explanation:
The torque caused by the gyroscope can be given by the relation,
r × f
The torque measured by the gyroscope varies directly with the distance, r.
A decrease in the distance r will also cause a decrease in the value of the torque measured. When the distance, r is reduced from 7.5 inches to 5 inches, the torque caused by the gyroscope's weight also reduces.
The weight of the gyroscope remains constant despite the reduction in the distance because the weight of the gyroscope is not a function of the distance from the gyroscope. Therefore, the spring scale will not read a different value.
Yes, the spring scale does not need to be measured from the center of mass location because the weight does not depend on the location of measurement. The reading of the sprig scale remains constant.