A car traveling in a straight line has a velocity of +4.4 m/s. after an acceleration of 0.65 m/s2 , the car's velocity is +8.3 m
/s. in what time interval did the acceleration occur? answer in units of s.
1 answer:
Answer:
1.53seconds
Explanation:
Using first equation of motion :
V=U + at
Where final velocity (V) =+8.3m/s
Initial velocity (U) =+4.4m/s
Acceleration (a) = 0.65m/s^2
time(s)=?
V=U + at
+8.3^2 = +4.4 + 0.65 * t
Making t the subject of the formula :
Therefore, t= ( +8.3 - 4.4)/0.65 = 1.53seconds
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