Question

A car traveling in a straight line has a velocity of +4.4 m/s. after an acceleration of 0.65 m/s2 , the car's velocity is +8.3 m/s. in what time interval did the acceleration occur? answer in units of s.

Answer 1

Answer:

1.53seconds

Explanation:

Using first equation of motion :

V=U + at

Where final velocity (V) =+8.3m/s

Initial velocity (U) =+4.4m/s

Acceleration (a) = 0.65m/s^2

time(s)=?

V=U + at

+8.3^2 = +4.4 + 0.65 * t

Making t the subject of the formula :

Therefore, t= ( +8.3 - 4.4)/0.65 = 1.53seconds