1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
lidiya [134]
4 years ago
9

If it takes 600 N to move a box 5 meters, how much work is done on the box?

Physics
1 answer:
Arada [10]4 years ago
6 0

Answer:3000joules

Explanation: work=force×distance

Work=600×5

Work=3000joules

You might be interested in
An object falls through the air, gaining speed as it falls. A student claims that this creates new energy, and so it breaks the
yKpoI14uk [10]

Answer:

D

Explanation:

Energy is never created nor destroyed.

4 0
3 years ago
Read 2 more answers
Points A, B, and C are at the corners of an equilateral triangle of side 8 m. Equal positive charges of 4 mu or micro CC are at
aliina [53]

Answer:

a) 8.99*10³ V  b) 4.5*10⁻² J c) 0 d) 0

Explanation:

a)

  • The electrostatic potential V, is the work done per unit charge, by the electrostatic force, producing a displacement d from infinity (assumed to be the reference zero level).
  • For a point charge, it can be expressed as follows:

        V =\frac{k*q}{d}

  • As the electrostatic force is linear with the charge (it is raised to first power), we can apply superposition principle.
  • This means that the total potential at a given point, is just the sum of the individual potentials due to the different charges, as if the others were not there.
  • In our case, due to symmetry, the potential, at any corner of the triangle, is just the double of the potential due to the charge located at  any other corner, as follows:

        V = \frac{2*q*k}{d} = \frac{2*8.99e9N*m2/C2*4e-6C}{8m} =\\ \\ V= 8.99e3 V

  • The potential at point C is 8.99*10³ V

b)

  • The work required to bring a positive charge of 5μC from infinity to the point C, is just the product of the potential at this point times the charge, as follows:

        W = V * q = 8.99e3 V* 5e-6C = 4.5e-2 J

  • The work needed is 0.045 J.

c)

  • If we replace one of the charges creating the potential at the point  C, by one of the same magnitude, but opposite sign, we will have the following equation:

       V = \frac{8.99e9N*m2/C2*(4e-6C)}{8m}  + (\frac{8.99e9N*m2/C2*(-4e-6C)}{8m}) = 0

  • This means that the potential due to both charges is 0, at point C.

d)

  • If the potential at point C is 0, assuming that at infinity V=0 also, we conclude that there is no work required to bring the charge of 5μC from infinity to the point C, as no potential difference exists between both points.
5 0
3 years ago
Calculate the mass of earth
Roman55 [17]

Answer:

m=6.85\times 10^{24}\ kg

Explanation:

The radius of Earth is 6.67\times 10^6\ m

The density of an object is given by :

d=\dfrac{m}{V}

The density of Erth is, d = 5515 kg/m³

Where

m is the mass of the Earth

So,

m=d\times V\\\\m=\dfrac{4}{3}\pi r^3\times d

Put all the values,

m=\dfrac{4}{3}\pi \times (6.67\times 10^6)^3\times 5515 \\\\m=6.85\times 10^{24}\ kg

So, the mass of the Earth is equal to 6.85\times 10^{24}\ kg.

6 0
3 years ago
A bicyclist makes a trip that consists of three parts, each in the same direction (due north) along a straight road. During the
Advocard [28]

Answer:

a

The total distance traveled is D  = 26760 \ m

b

The average velocity is  v_{avg} =  6.8 \ m/s

Explanation:

From the question we are told that

     The time taken for first part t_1 =  22 \ minutes = 22*60 = 1320 \ s

      The speed for the first part is  v_1 =  7.2 \ m/s

        The time taken for second part is t_2 =  36 \ minutes =  2160 \ s

        The speed for the second  part is  v_2 =  5.1 \ m/s

         The time taken for third  part is  t_3 =  8 \ minutes = 480 \ s  

          The speed for the third  part is  v_3 =  13 m/s

Generally

        distance(D)  =  velocity * time

Therefore the total distance traveled is  

         D  =  (v_1 * t_1) + (v_2 * t_2 ) + (v_3 * t_3)

substituting values

        D  =  (7.2 * 1320) + (5.1 * 2160) + (13 * 480)

        D  = 26760 \ m

Generally the average velocity is mathematically represented as

        v_{avg} =  \frac{D}{t_{total}}

Where t_{total} is the total time taken which is mathematically represented as

       t_{total}  =  1320 + 2160 + 480

      t_{total}  =3960\ s

The average velocity is

        v_{avg} =  \frac{26760}{3960}

        v_{avg} =  6.8 \ m/s

   

8 0
3 years ago
Please help :) Thanks if you do!
Naddika [18.5K]

Answer:

moving

Explanation:

They've been moving for thousands and thousands of years. Millions of years ago there was a land called Pangea that seperated into the continents we see today.

7 0
3 years ago
Read 2 more answers
Other questions:
  • Consider a perfectly insulated cup (no
    7·1 answer
  • Predict what the MASS would be of something exerting a force of 45N on a spring scale. EXPLAIN how you got
    15·1 answer
  • How do we know the sun rotate
    8·2 answers
  • What is the potential energy of a 2 kg plant that is on a windowsill 1.3 m high
    11·1 answer
  • Suppose you throw a rock off a cliff on Earth with an initial horizontal velocity of 3 m/s. Assuming minimal drag and no wind, t
    6·2 answers
  • 5 A truck travelling at 25 m/s puts on its brakes for 4 s. This produces an acceleration of –2 m/s. What is the truck's
    5·1 answer
  • The bus lay 40 km at a speed of 72 km / h, and then another 60 km at a speed of 30 m / s. Determine the average speed of the bus
    5·1 answer
  • PLS ANSWER WITH EXPLANATION OR SOLUTION (WILL GIVE 50 PTS)
    8·1 answer
  • What are the people and places that help determine a persons view of the world reffered to as
    11·2 answers
  • What does the area under the velocity-time graph represent.
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!