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Bas_tet [7]
2 years ago
11

Which is a characteristic of nuclear fission?

Chemistry
1 answer:
s2008m [1.1K]2 years ago
7 0

Answer:

Contrasting Nuclear Fission and Nuclear Fusion

Nuclear FissionByproducts of the reaction: Fission produces many highly radioactive particles.Conditions: Critical mass of the substance and high-speed neutrons are required.Energy Requirement: Takes little energy to split two atoms in a fission Explanation:

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If the speed of a sound wave increases what other property of the wave must also increase when all other wave properties are hel
kati45 [8]
<h2>Frequency</h2>

Explanation:

Wave frequency is the number of waves that pass a fixed point in a given amount of time.

Wave speed is the speed at which a wave travels.

Let the wave speed be v

Let the wave frequency be f

Let the wave length be l

The wave speed,frequency and wave length are related by the equation v=f\times l.

When v increases,f increases on the other side to maintain equality when no other property is changing.

8 0
3 years ago
Please help i will give 20 points
NNADVOKAT [17]

Answer:

It's A., thats conduction and its a heat transfer

Explanation:

6 0
2 years ago
If 2 acid have ph value 3 and 5 respectively, which will be more acidic? Why?​
nataly862011 [7]

Answer:

A lower ph is always more acidic, due to the increased concentration of hydrogen ions in the solution/substance.

A ph of 3 is 100 times more acidic than a pH of 5, and this is due to the increments on the scale.

6 0
3 years ago
what is the structure of XeO2F2???i know its hybridization as sp3d but cannot quite understand its diagram in free space,help an
skelet666 [1.2K]
The shape of XeO₂F₂ is Trigonal bi-pyramidal see-saw tetrahedron (see attached pictures)
- As you said the hybridization of Xe here is sp³d so its geometry has to be Trigonal bi-pyramidal in which F atom located on axial positions but for the final shape we exclude lone pair on Xe to give see-saw shape (see second picture) 
- Remember that we have 5 pairs (4 bond pairs + 1 lone pair) and we have to place lone pair at equatorial position.

6 0
3 years ago
Determine the work done by an ideal gas while expanding by a volume of 0.25 L against an external pressure of 1.50 atm (assume a
Sliva [168]

Answer : The value of work done by an ideal gas is, 37.9 J

Explanation :

Formula used :

Expansion work = External pressure of gas × Volume  of gas

Expansion work = 1.50 atm × 0.25 L

Expansion work = 0.375 L.atm

Conversion used : (1 L.atm = 101.3 J)

Expansion work = 0.375 × 101.3 = 37.9 J

Therefore, the value of work done by an ideal gas is, 37.9 J

6 0
3 years ago
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