The change of energy : 4.8744 x 10⁺¹⁹ J
<h3>Further explanation</h3>
Radiation energy is absorbed by photons
The energy in one photon can be formulated as

Where
h = Planck's constant (6,626.10⁻³⁴ Js)
f = Frequency of electromagnetic waves
f = c / λ
c = speed of light
= 3.10⁸
λ = wavelength
The wavelength is 4078 A = 4.078 x 10⁺⁷ m

Answer:
components of a nucleotide - DNA and RNA
One of the things that Revolution causes is seasons
Answer:
0.0847M is molarity of sodium hydrogen citrate in the solution
Explanation:
The 2.0%(w/v) solution of sodium hydrogen citrate contains 2g of the solute in 100mL of solution. To find the molarity of the solution we need to convert the mass of solute to moles using molar mass and the mL of solution to Liters because molarity is the ratio between moles of sodium hydrogen citrate and liters of solution.
<em>Moles Na2C6H6O7:</em>
<em>Molar Mass:</em>
2Na: 2*22.99g/mol: 45.98g/mol
6C: 6*12.01g/mol: 72.01g/mol
6H: 6*1.008g/mol: 6.048g/mol
7O: 7*16g/mol: 112g/mol
45.98g/mol + 72.01g/mol + 6.048g/mol + 112g/mol = 236.038g/mol
Moles of 2g:
2g * (1mol / 236.038g) = <em>8.473x10⁻³ moles</em>
<em />
<em>Liters solution:</em>
100mL * (1L / 1000mL) = <em>0.100L</em>
<em>Molarity:</em>
8.473x10⁻³ moles / 0.100L =
<h3>0.0847M is molarity of sodium hydrogen citrate in the solution</h3>
Answer: (a) BE = 1.112 MeV
(b) BE = 7.074 MeV
(c) BE = 7.767 MeV
(d) BE = 8.112 MeV
Explanation: Binding energy per nucleon is the average energy necessary to remove a proton or a neutron from the nucleus of an atom. It is mathematically defined as:

Where
Δm is a difference in mass known as <u><em>mass</em></u><em> </em><u><em>defect</em></u>
A is atomic mass of an atom.
Mass Defect is determined by:

where:
Z is atomic number
is mass of proton
is mass of neutron
is mass of the nucleus
Mass of proton is 1.007825u.
Mass of neutron is 1.008665u.
The unit u is equal to 931.5MeV/c².
(a) 2H(deuterion): Given: Z = 1; A = 2;
= 2.014102u



BE = 1.112MeV
(b) 4He (Helium): Given: Z = 2; A = 4;
= 4.002603



BE = 7.074MeV
(c) 18O (Oxygen): Given: Z = 8; A = 18;
= 17.999160



BE = 7.767MeV
(d) 23Na (Sodium): Given: Z = 11; A = 23;
= 22.989767



BE = 8.112MeV