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Mumz [18]
2 years ago
10

What rule/principle States that electrons fill orbital from lowest energy to highest energy?

Chemistry
2 answers:
KonstantinChe [14]2 years ago
5 0

Answer:

a

Explanation:

Flauer [41]2 years ago
3 0
The aufbau principle, from the German Aufbauprinzip (building-up principle), also called the aufbau rule, states that in the ground state of an atom or ion, electrons fill atomic orbitals of the lowest available energy levels before occupying higher levels.
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What is the change of energy where the wavelength is 4078 A
Leni [432]

The change of energy : 4.8744 x 10⁺¹⁹ J

<h3>Further explanation</h3>

Radiation energy is absorbed by photons

The energy in one photon can be formulated as

\large{\boxed{\bold{E\:=\:h\:.\:f}}}

Where

h = Planck's constant (6,626.10⁻³⁴ Js)

f = Frequency of electromagnetic waves

f = c / λ

c = speed of light

= 3.10⁸

λ = wavelength

The wavelength is 4078 A = 4.078 x 10⁺⁷ m

\tt E=h.\dfrac{c}{\lambda}\\\\E=6.626\times 10^{-34}\times \dfrac{3.10^8}{4.078\times 10^{-7}}\\\\E=4.8744\times 10^{-19}~J

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2 years ago
What are the components of a nucleotide
balandron [24]

Answer:

components of a nucleotide - DNA and RNA

7 0
3 years ago
Read 2 more answers
What three thing does earth revolution causes?
Blababa [14]
One of the things that Revolution causes is seasons
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3 years ago
A 2.0% (w/v) solution of sodium hydrogen citrate, Na2C6H6O7, which also contains 2.5% (w/v) of dextrose, C6H12O6, is used as an
tamaranim1 [39]

Answer:

0.0847M is molarity of sodium hydrogen citrate in the solution

Explanation:

The 2.0%(w/v) solution of sodium hydrogen citrate contains 2g of the solute in 100mL of solution. To find the molarity of the solution we need to convert the mass of solute to moles using molar mass and the mL of solution to Liters because molarity is the ratio between moles of sodium hydrogen citrate and liters of solution.

<em>Moles Na2C6H6O7:</em>

<em>Molar Mass:</em>

2Na: 2*22.99g/mol: 45.98g/mol

6C: 6*12.01g/mol: 72.01g/mol

6H: 6*1.008g/mol: 6.048g/mol

7O: 7*16g/mol: 112g/mol

45.98g/mol + 72.01g/mol + 6.048g/mol + 112g/mol = 236.038g/mol

Moles of 2g:

2g * (1mol / 236.038g) = <em>8.473x10⁻³ moles</em>

<em />

<em>Liters solution:</em>

100mL * (1L / 1000mL) = <em>0.100L</em>

<em>Molarity:</em>

8.473x10⁻³ moles / 0.100L =

<h3>0.0847M is molarity of sodium hydrogen citrate in the solution</h3>
3 0
2 years ago
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For each of the following nuclei, determine the binding energy per nucleon (in MeV). (For all masses, keep six places beyond the
garik1379 [7]

Answer: (a) BE = 1.112 MeV

               (b) BE = 7.074 MeV

               (c) BE = 7.767 MeV

               (d) BE = 8.112 MeV

Explanation: Binding energy per nucleon is the average energy necessary to remove a proton or a neutron from the nucleus of an atom. It is mathematically defined as:

BE = \frac{\Delta m.c^{2}}{A}

Where

Δm is a difference in mass known as <u><em>mass</em></u><em> </em><u><em>defect</em></u>

A is atomic mass of an atom.

Mass Defect is determined by:

\Delta m =Zm_{p}+(A-Z)m_{n} - m_{nuc}

where:

Z is atomic number

m_{p} is mass of proton

m_{n} is mass of neutron

m_{nuc} is mass of the nucleus

Mass of proton is 1.007825u.

Mass of neutron is 1.008665u.

The unit u is equal to 931.5MeV/c².

(a) 2H(deuterion): Given: Z = 1; A = 2; m_{nuc} = 2.014102u

\Delta m =1(1.007825)+1(1.008665) -2.014102

\Delta m =0.002388u

BE = \frac{0.002388.c^{2}}{2}.931.5\frac{MeV}{c^{2}}

BE = 1.112MeV

(b) 4He (Helium): Given: Z = 2; A = 4; m_{nuc} = 4.002603

\Delta m =2(1.007825)+2(1.008665) -4.002603

\Delta m =0.030377u

BE = \frac{0.030377.c^{2}}{4}.931.5\frac{MeV}{c^{2}}

BE = 7.074MeV

(c) 18O (Oxygen): Given: Z = 8; A = 18; m_{nuc} = 17.999160

\Delta m =8(1.007825)+10(1.008665) -17.999160

\Delta m =0.15009u

BE = \frac{0.15009.c^{2}}{18}.931.5\frac{MeV}{c^{2}}

BE = 7.767MeV

(d) 23Na (Sodium): Given: Z = 11; A = 23; m_{nuc} = 22.989767

\Delta m =11(1.007825)+12(1.008665) -22.989767

\Delta m =0.200288u

BE = \frac{0.200288.c^{2}}{23}.931.5\frac{MeV}{c^{2}}

BE = 8.112MeV

3 0
3 years ago
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