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LenKa [72]
2 years ago
5

Now write a short paragraph comparing "fast" to "speeding up quickly" and "slow" to "speeding up slowly".

Physics
1 answer:
ahrayia [7]2 years ago
6 0

Answer:ok yes

Explanation:yes of course

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Blake is setting up his tent at a renaissance fair. If the tent is 8 feet tall and the tether can be staked no more than 2 feet
Mariana [72]
The stake, height and tether length of the tent form a right angle triangle where the tether length is the hypotenuse.
Applying Pythagoras theorem:
length² = height² + (stake distance)²
length = √(8² + 2²)
length = 8.5 feet
3 0
2 years ago
What is the speed of a bobsled whose distance-time graph indicates that it traveled 113m in 29s?
Elza [17]
In this item, we are asked to determine the speed of the bobsled given the distance traveled and the time it takes to cover the certain distance. This can mathematically be expressed as,
                          speed = distance / time

Substituting the given values in this item,
                         speed = (113 m) / (29 s)
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<em>ANSWER: 3.90 m/s</em>
3 0
3 years ago
A rock is suspended by a light string. When the rock is in air, the tension in the string is 43.8 N . When the rock is totally i
sergeinik [125]

Answer:

Density of unknown liquid is 2047 kg/m^3

Explanation:

When rock is suspended in air then the weight of the rock is counter balanced by the tension force in the string

So here we have

T = mg = 43.8 N

now when the rock is immersed in water then the tension in the string is and buoyancy force due to water is counter balanced by the weight of the object

so here we have

T_1 + F_b = mg

31.3 + F_b = 43.8

F_b = 43.8 - 31.3 = 12.5 N

now we have

(1000)V(9.81) = 12.5

V = 1.27 \times 10^{-3} m^3

now when the rock is immersed into other liquid then we have

T_2 + F_b' = mg

18.3 + F_b' = 43.8

F_b' = 25.5 N

now we have

\rho(1.27 \times 10^{-3})(9.81) = 25.5

\rho = 2047 kg/m^3

4 0
3 years ago
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Explanation:

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thanks for the point

8 0
2 years ago
Read 2 more answers
Examples of tension force
Mashutka [201]
Pulling the two ends of a rubber band further and further apart from each other.
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3 years ago
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