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DiKsa [7]
3 years ago
7

1. How would the motion of a pendulum change at high altitude like a high mountain top? How would the motion change under weight

less conditions?
Physics
1 answer:
gavmur [86]3 years ago
6 0

Answer:

A pendulum moves with the principle of small angles that show that the frequency and period of the pendulum are not dependent on the initial angular displacement of the mass it carries.

On a high mountain top, a reduced force of gravity is exerted on the mass, therefore, producing long periods of oscillation on the pendulum.

However, under weightless conditions where gravity is zero, the pendulum will not work as what keeps the mass in oscillation is gravity. If therefore gravity is absent there can be no oscillation.

Explanation:

On a high mountain top, a reduced force of gravity is exerted on the mass, therefore, producing long periods of oscillation on the pendulum.

However, under weightless conditions where gravity is zero, the pendulum will not work as what keeps the mass in oscillation is gravity. If therefore gravity is absent there can be no oscillation.

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How far moves in 95g ball by applying 200 Newton Force if 14 KJ of energy is transferred​
Sunny_sXe [5.5K]

Answer.....

Explanation:

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3 years ago
QUESTION 1
frez [133]
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3 years ago
What characteristics are shared by both heating and cooling curves? choose 4
Luda [366]

The characteristics shared by both heating and cooling curves is that phases changes when the temperature stays the same.

<h3>What is heating and cooling?</h3>

Heating is the process by which the temperature of a place or substances or object is increased.

Cooling Is the process of lowering the temperature of a substance or object by using conditioners or by freezing .

Therefore, The characteristics shared by both heating and cooling curves is that phases changes when the temperature stays the same.

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6 0
2 years ago
You are unloading a refrigerator from a delivery van. The ramp on the van is 5.0 mm long, and its top end is 1.4 mm above the gr
Ivahew [28]

Answer:

Work done is 1.31 J.

Explanation:

Given:

Length of the ramp (L) = 5.0 mm

Height of the top end (H) = 1.4 mm

Horizontal force applied (F) = 270 N

Work done (W) = ?

We know that,

Work done is equal to the product of force and displacement caused along the line of application of force.

Here, the force acting on the refrigerator is in the horizontal direction while the refrigerator is moving down along the length of the ramp. So, we have to first find the horizontal component of the displacement caused.

Now, consider the triangle ABC representing the given situation. The point A is the top end point of the ramp, AB is the length of the ramp, AC is the vertical displacement of the refrigerator and BC is the horizontal displacement of the refrigerator.

Using Pythagoras theorem,

AB^2=BC^2+AC^2\\\\(5.0)^2=BC^2+(1.4)^2\\\\BC=\sqrt{25.0-1.96}\\\\BC=4.86\ mm

Now, force applied on the refrigerator is in the direction opposite to the horizontal component of displacement. So, work is negative.

Work = Force × Horizontal displacement

W=270\ N\times 4.86\ mm\\\\W=1312.2\ \textrm{N-mm}\\\\W=1.31\ J\ \ \ \ \ \textrm{ [1 mm = 0.001 m]}

Therefore, work done is 1.31 J.

7 0
3 years ago
Below is a circuit schematic of sources and resistors (Figure 3). VS = 10V , R1 = 100Ω, R2 = 50Ω, R3 = 25Ω, IS = 2A. Calculate t
lorasvet [3.4K]

Answer:

V_3\approx 4.28\,\,V

I_1=0.0572\,\,amps

I_3\approx 0.171\,\,amps

Explanation:

Notice that this is a circuit with resistors R1 and R2 in parallel, connected to resistor R3 in series. It is what is called a parallel-series combination.

So we first find the equivalent resistance for the two resistors in parallel:

\frac{1}{Re}= \frac{1}{R1}+\frac{1}{R2}\\\frac{1}{Re}= \frac{1}{100}+\frac{1}{50}\\\frac{1}{Re}= \frac{3}{100}\\Re=\frac{100}{3} \,\,\Omega

By knowing this, we can estimate the total current through the circuit,:

Vs=I\,*\,(\frac{100}{3} +25)\\10=I\,*\,\frac{175}{3} \\I=\frac{30}{175} \,amps

So approximately 0.17  amps

and therefore, we can estimate the voltage drop (V3) in R3 uisng Ohm's law:

V_3=\frac{30}{175} *\,25=\frac{30}{7} \approx 4.28\,\,V

So now we know that the potential drop across the parellel resistors must be:

10 V -  4.28 V = 5.72 V

and with this info, we can calculate the current through R1 using Ohm's Law:

I_1=\frac{V_1}{R_1} =\frac{5.72}{100} =0.0572\,\,amps

4 0
4 years ago
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