Answer:
d). The value of y should be -32m
Vx=0.92 m/s
Explanation:
Using equation of motion uniform to y motion
So to find t that is the same time for all the motion
The value of Xf=-3.2m because the g is negative from the axis
Now in the axis 'x' to find Vx
Answer:
= 0.517 m
Explanation:
This is a resonance exercise where the ends of the string are fixed, therefore it has a node of them, the fundamental (longest) wavelength created has the form
λ = 2L
wave speed is related to wavelength and frequency
v = λ f
v = 2L f
let's calculate
v = 2 0.50 440
v = 440 m / s
since they indicate that the tension of the string does not change and the linear density of the string is constant, the speed of the wave also remains constant
f =
let's find the length for the new resonance frequency
L =
let's calculate
L =
L = 0.5166 m
Answer:
continual drift
Explanation:
it exsplain why the tectonic plates move
Answer:
36N
Explanation:
First draw a diagram so you can see which forces act in which direction.
Then define which is your positive direction. I chose the direction of accelleration (downward) to be positive. This means that the weight of the object is also acting in the positive direction but Tension is acting in the negative direction.
If the elevator which contains the object within is accellerating at 2.6 ms^-2 then the object and string system is also accellerating at the same rate.
F = ma where F is the resultant force.
Resultant for is Weight + Tension but tension is in the negative direction so
F = mg -T
F = 5g - T
F = ma so F = 5 x 2.6
13 = 5g-T
T = 5g - 13
T = 36N
(I've taken g = 9.8ms^-2 but if this is for a physics class I'd take it to be 9.81ms^-2)