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zalisa [80]
3 years ago
12

A net force xf acts on an object. what does this mean?

Physics
1 answer:
NISA [10]3 years ago
8 0
<span>Answer: 6- for an object to accelerate, Newton's law #2 tells us there must be a force acting on it. F=ma the effect of a force is to accelerate the mass . It cannot be 1, because the force must be centripetal to move the object in a circle. it can't be 2 because if an object is accelerating the velocity cannot be constant as it is moving faster. It can't be 3 because a stationary object has a net force of 0. 4 has nothing to do with the question. 5- no force is needed for uniform motion. 7- that is impossible.</span>
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Mass can be considered concentrated at the center of mass for rotational motion.Select one:TrueFalse
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iIn this case the mass of a body cannot be considered to be concentrated at the centre of mass of the body for the purpose of computing the rotational motion

Therefore the answer is False

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1 year ago
The pressure of a gas produces a net force (the sum of all the forces) at ____ angles to the wall of a container.
ivanzaharov [21]

Answer: RIGHT angles

Explanation:

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3 years ago
A 35 g steel ball is held by a ceiling-mounted electromagnet 4.0 m above the floor. A compressed-air cannon sits on the floor, 4
HACTEHA [7]

Answer:

7.9 m/s

Explanation:

When both balls collide, they have spent the same time for their motions.

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This is purely under gravity. It is vertical.

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Distance, <em>s</em> = 4.0 m - 1.2 m = 2.8 m

Acceleration, <em>a</em> = g

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Motion of plastic ball

This has two components: a vertical and a horizontal.

The vertical motion is under gravity.

Considering the vertical motion,

Initial velocity, <em>u </em>= ?

Distance, <em>s</em> = 1.2 m

Acceleration, <em>a</em> = -<em>g                   </em> (It is going up)

Using the equation of motion

s = ut+\frac{1}{2}at^2

1.2\text{ m} = ut-\frac{1}{2}gt^2

Substituting the value of <em>t</em> from the previous equation,

1.2\text{ m} = u\sqrt{\dfrac{5.6}{g}}-\dfrac{1}{2}\times g\times\dfrac{5.6}{g}

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u = \dfrac{4.0}{0.756} = 5.29 \text{ m/s}

This is the vertical component of the initial velocity

Considering the horizontal motion which is not accelerated,

horizontal component of the initial velocity is horizontal distance ÷ time.

u_h = \dfrac{4.4\text{ m}}{0.756\text{ s}} = 5.82\text{ m/s}

The initial velocity is

v_i = \sqrt{u^2+u_h^2} = \sqrt{(5.29\text{ m/s})^2+(5.82\text{ m/s})^2} = 7.9 \text{ m/s}

4 0
3 years ago
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Komok [63]

Answer:

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5 0
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Lesechka [4]
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