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zalisa [80]
4 years ago
12

A net force xf acts on an object. what does this mean?

Physics
1 answer:
NISA [10]4 years ago
8 0
<span>Answer: 6- for an object to accelerate, Newton's law #2 tells us there must be a force acting on it. F=ma the effect of a force is to accelerate the mass . It cannot be 1, because the force must be centripetal to move the object in a circle. it can't be 2 because if an object is accelerating the velocity cannot be constant as it is moving faster. It can't be 3 because a stationary object has a net force of 0. 4 has nothing to do with the question. 5- no force is needed for uniform motion. 7- that is impossible.</span>
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Tripling the displacement from equilibrium of an object in simple harmonic motion will change the magnitude of the object’s maxi
SVEN [57.7K]
A (max)= A (2pi/T)
a (max)= maximum acceleration
A= amplitude
T= periodic time

by definition, amplitude is the displacement from equillibrium point.

we see that maximum acceleration is directly proportional to the amplitude. so tripling the amplitude will triple the maximum acceleration.
5 0
4 years ago
A 2 kg watermelon is dropped from a 4 m tall roof. How fast will the watermelon be moving as it strikes the ground below?
Volgvan

Answer:

8.85m/s

Explanation:

v=√2gh

v=√2×9.8×4

v=8.85m/s

3 0
3 years ago
Resolving power of a telescope whose objective lens has diameter 1.22m for a wavelength 4000 Å.​
Mamont248 [21]

\sf \huge \purple{ Answer : - }

Diameter of objective lens = 1.22m

Wavelength of light = 4000Å

We have to find resolving power of telescope ..

★ Resolving power of telescope is given by

RP = D/1.22λ

  • D denotes diameter of lens
  • λ denotes wavelength of light

RP = D/1.22λ

RP = (1.22×10⁷)/(1.22×4)

RP = 0.25 × 10⁷

RP = 2.5 × 10⁶

★ Resolving power of microscope is given by

RP = 2μsinθ/λ

5 0
3 years ago
Where could light travel the easiest and fastest?
madreJ [45]

Explanation:

Light travels fastest through air

3 0
3 years ago
Read 2 more answers
A helium-neon laser (λ = 633 nm) illuminates a single slit and is observed on a screen 1.50 m behind the slit. The distance betw
mario62 [17]

Answer:

0.2 mm

Explanation:

As we know that

Y = \frac{m\lambda * D}{d}

where

m represents  the order of minimum

y represents the  distance on the screen of the minimum from central axis

λ is the wavelength  of the light

D is the distance between  screen-to-slit

d represents the width of the slit

For first minima

y_1 = \frac{1 * 633 * 10^{-9}*1.5}{d}

For second minima

y_2 = \frac{2 * 633 * 10^{-9}*1.5}{d}

Y_2 - Y_1 = 0.00475m\\\frac{633 * 10^{-9} * 1.5 }{d} = 0.00475\\d = 0.0002 m\\d = 0.2 mm

3 0
3 years ago
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