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dimulka [17.4K]
2 years ago
10

State the reason why the magnetic field strength of a magnet is greatest at the poles​

Physics
1 answer:
icang [17]2 years ago
5 0

Answer:

As shown above, the magnetic field is strongest near to the poles of the magnet were the lines of flux are more closely spaced. The general direction for the magnetic flux flow is from the North ( N ) to the South ( S ) pole.

Explanation:

please give me brainlist and follow

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Charges q, q, and – q are placed on the x-axis at x = 0, x = 4 m, and x = 6 m, respectively. At which of the following points do
MrRissso [65]

Answer:

can you show a graph but if not i believe the answer is x=6m

Explanation:

7 0
3 years ago
A bell is rung. What best describes the density of air around the bell? The air density does not change. The air density increas
dezoksy [38]

I think the closest possible answer to this question is The air density increases and decreases repeatedly before returning to normal.Thank you for your question. Please don't hesitate to ask in Brainly your queries. 
7 0
3 years ago
Read 2 more answers
A 1.5m wire carries a 4 A current when a potential difference of 66 V is applied. What is the resistance of the wire?
kifflom [539]
Resistance = Voltage / current
Resistance = 66/4
=16.5ohms
Pls mark as brainliest
3 0
3 years ago
The 60.0 kg skier shown below is skiing down a 35.0 degree incline where the magnitude of the friction force is 38.5N
Sunny_sXe [5.5K]

Answer:

a) 4.98m/s²

b) 481.66N

Explanation:

a) Using the Newtons second law of motion

\sum F_x = ma_x\\F_m - F_f = ma_x\\Wsin \theta - F_f = ma_x\\mgsin \theta - F_f = ma_x\\

m is the mass of the object

g is the acceleration due to gravity

Fm is the moving force acting along the plane

Ff is the frictional force opposing the moving froce

a is the acceleration of the skier

Given

m = 60kg

g = 9.8m/s²

\theta = 35°

Ff = 38.5N

Required

acceleration of the skier a

Substituting into the formula;

60(9.8)sin 35^0 - 38.5 = 60a\\588sin35^0 - 38.5 = 60a\\337.26 - 38.5 = 60a\\298.76 = 60a\\a = 298.76/60\\a = 4.98m/s^2\\

Hence the acceleration of the skier is 4.98m/s²

b) The normal force on the skier is expressed as;

N = Wcosθ

N = mgcosθ

N = 60(9.8)cos 35°

N = 588cos 35°

N = 481.66N

Hence the normal force on the skier is 481.66N

5 0
3 years ago
1. How much force is needed to accelerate a 66 kg skier<br> at 2 m/sec2?
Tju [1.3M]

Answer:

<h2>132 N</h2>

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 66 × 2

We have the final answer as

<h3>132 N</h3>

Hope this helps you

3 0
3 years ago
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