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3 years ago

If a layer was deposited but does not appear in the rock record, what has occured

2 answers:

7 0

Erosion. Erosion is the action and movement of a surface process (e.g. water or wind) that removes and transports a material layer from one location to another. Once eroded, the deposited layer will not appear in the rock record.

nalin [4]3 years ago

5 0

I think you forgot to give the choices along with the question. I am answering the question based on my research and knowledge. If a layer was deposited but does not appear in the rock record, the thing that happened is erosion. I hope that this is the ans wer that has actually come to your desired help.

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gayaneshka [121]

There are three main ways a late or missed payment can impact you financially: You can be charged late payment fees. You may face having the interest rate on your card raised to the penalty rate. Your late payment may be added to your credit history and can end up affecting your credit score.

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3 years ago

In what year will there be 8 billion people in the world? 2020 2022 2024 2030

Morgarella [4.7K]

Answer:

2030

Explanation:

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2 years ago

Read 2 more answers

For rectilinear motion the relationship between displacement, s, velocity, v, acceleration, a, and time, t, s = s0 + v0t + (1/2)

stiv31 [10]

The rectilinear motion is given as:

s = s0 + v0 t + (1/2) a t^2

We can see that the variables stand for:

s = final distance

s0 = initial distance

v0 = initial velocity

t = time

a = acceleration

We can see that all these variable are always constant EXCEPT acceleration. The rectilinear motion can only be applied if and only if acceleration is CONSTANT.

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3 years ago

Need helppp number 5

horsena [70]

Answer:

1768 meters

Explanation:

Distance = speed x time.

(340 m/s) x (5.2 s) = 1768 m

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2 years ago

Read 2 more answers

Am radio signals have frequencies between 550 khz and 1600 khz (kilohertz) and travel with a speed of 3.00 ✕ 108 m/s. what are t

Allisa [31]

The minimum frequency is
$f_1 = 550 kHz = 5.50 \cdot 10^5 Hz$
while the maximum frequency is
$f_2 = 1600 kHz = 1.6 \cdot 10^6 Hz$
Using the relationship between frequency f of a wave, wavelength $\lambda$ and the speed of the wave v, we can find what wavelength these frequencies correspond to:
$\lambda_1 = \frac{v}{f_1}= \frac{3 \cdot 10^8 m/s}{5.5 \cdot 10^5 Hz}=545 m$
$\lambda_2 = \frac{v}{f_2}= \frac{3 \cdot 10^8 m/s}{1.6 \cdot 10^6 Hz}=188 m$

So, the wavelengths of the radio waves of the problem are within the range 188-545 m.

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2 years ago