Answer:
There are 0.1 moles of solute in 250 mL of 0.4 M solution.
Explanation:
First, recognize that the molar concentration tells you how many moles of the solute are present in one liter of solution. In a 0.4 M solution, there are 0.4 moles of solute in every liter of solution. You can determine the number of moles of solute in 250 mL of the solution using dimensional analysis.
250
ml . 1L/1000 L . 0.4mol / 1L
Units of liters and milliliters cancel, leaving you with a final answer in units of moles, at 0.1 mol.
The Km is the MIchealis-Menten constant and this represents the affinity of the enzyme to its substrate. The higher the value for Km, the higher is the affinity of the enzyme to a substrate and the greater is the rate of reaction. Hexokinase IV has a higher Km than other hexokinases because it has a higher affinity to hexose substrates.
Answer:
Gears A and B work together. Gear A turns 30 times when Gear B turns 45 times. When Gear B turns 12 times, how many times does Gear A turn?
Answer:
0.027 mole of NaOH.
Explanation:
We'll begin by obtaining the number of mole H2SeO4 in 45mL of 0.30M H2SeO4
This is illustrated below:
Molarity of H2SeO4 = 0.3M
Volume of solution = 45mL = 45/1000 = 0.045L
Mole of H2SeO4 =...?
Mole = Molarity x Volume
Mole of H2SeO4 = 0.3 x 0.045
Mole of H2SeO4 = 0.0135 mole
Next, the balanced equation for the reaction. This is given below:
H2SeO4 + 2NaOH –> Na2SeO4 + 2H2O
From the balanced equation above,
1 mole of H2SeO4 required 2 moles of NaOH.
Therefore, 0.0135 mole of H2SeO4 will require = 0.0135 x 2 = 0.027 mole of NaOH.
Therefore, 0.027 mole of NaOH is needed for the reaction.
