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Sav [38]
3 years ago
15

An iminium ion is formed as an intermediate in a stork enamine reaction. the iminium is subsequently hydrolyzed with water. comp

lete the curved arrow pushing mechanism for the hydrolysis of the iminium below by adding any missing atoms, bonds, charges, non-bonding electron pairs, and curved arrows.

Chemistry
1 answer:
Dvinal [7]3 years ago
7 0
Below is the mechanism showing the hydrolysis of Iminium Ion into aldehye. The arrows are shown in RED.

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What occurs in order to break the bond in a cl2 molecule? explanation please.
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A cl2 molecule is a diatomic molecule composed of two atoms of identical halogen - chlorine. In this case, this molecule is composed of covalent bonds in which the identical atom- molecule tells that this is also non-polar. To break the bond, energy has to be absorbed to break the intermolecular force that bound the molecule together. 
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The space shuttle___.
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Answer:

goes very fast and carries astronauts

Explanation:

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Which type of bond is present in hydrogen sulfide (H2S)? The table of electronegativities is given
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Bonds formed between atoms can be classified as ionic and covalent

Ionic bonds are formed between atoms that have a high difference in the electronegativity values.

In contrast, bonds formed between atoms that have a difference in electronegativity lower than the ionic counterparts are polar covalent bonds.  If the atoms have very similar electronegativities, they form non-polar covalent bonds.

In H2S, the S atom is bonded to 2 H atoms. The electronegativity of H = 2.2 and S= 2.56. Since the difference is not high the bond formed will be covalent (polar covalent).

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In acidic aqueous solution, the purple complex ion Co(NH3)5Br2+ undergoes a slow reaction in which the bromide ion is replaced b
kirill115 [55]

Answer:

A) 0.065 M is its molarity after a reaction time of 19.0 hour.

B) In 52 hours [Co(NH_3)5Br]^{2+} will react 69% of its initial concentration.

Explanation:

Co(NH_3)_5(H_2O)_3+[Co(NH_3)5Br]^{2+}(Purple)(aq)+H_2O(l)\rightarrow [Co(NH_3)_5(H_2O)]^{3+}(Pinkish-orange)(aq)+Br^-(aq)

The reaction is first order in [Co(NH_3)5Br]^{2+}:

Initial concentration of [Co(NH_3)5Br]^{2+}= [A_o]=0.100 M

a) Final concentration of [Co(NH_3)5Br]^{2+} after 19.0 hours= [A]

t = 19.0 hour = 19.0 × 3600 seconds ( 1 hour = 3600 seconds)

Rate constant of the reaction = k = 6.3\times 10^{-6} s^{-1}

The integrated law of first order kinetic is given as:

[A]=[A_o]\times e^{-kt}

[A]=0.100 M\times e^{-6.3\times 10^{-6} s^{-1}\times 19.0\times 3600 s}

[A]=0.065 M

0.065 M is its molarity after a reaction time of 19.0 h.

b)

Initial concentration of [Co(NH_3)5Br]^{2+}= [A_o]=x

Final concentration of [Co(NH_3)5Br]^{2+} after t = [A]=(100\%-69\%) x=31\%x=0.31x

Rate constant of the reaction = k = 6.3\times 10^{-6} s^{-1}

The integrated law of first order kinetic is given as:

[A]=[A_o]\times e^{-kt}

0.31x=x\times e^{-6.3\times 10^{-6} s^{-1}\t}

t = 185,902.06 s = \frac{185,902.06 }{3600} hour = 51.64 hours ≈ 52 hours

In 52 hours [Co(NH_3)5Br]^{2+} will react 69% of its initial concentration.

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Which of the following is NOT a property of acids?
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E

It does all those things

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