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cluponka [151]
3 years ago
15

A 7th grade science class placed three large grade A eggs into beakers and recorded the mass. They then filled one beaker with v

inegar, one with corn syrup, and one with distilled water. After 5 days, they recorded the new masses of the eggs. This can be seen in the chart below. What are the independent variable, dependent variable, and constants?
Chemistry
1 answer:
lisov135 [29]3 years ago
3 0
Independent- The vinegar,corn syrup, distilled water
Dependent- The mass of the egg
Constant- the egg and the beaker 


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Isotope Atomic Mass (amu) Percent Abundance
exis [7]

Answer:

The average atomic mass is closer to Si- 28 because this isotope is present in more percentage in the sample.

Explanation:

Given data:

Atomic mass of silicon= ?

Percent abundance of Si-28 = 92.21%

Atomic mass of Si-28 = 27.98 amu

Percent abundance of Si-29 = 4.70%

Atomic mass of  Si-29 = 28.98 amu

Percent abundance of Si-30 = 3.09%

Atomic mass of  Si-30 = 29.97 amu

Solution:

Average atomic mass = (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass)+(abundance of 2nd isotope × its atomic mass)  / 100

Average atomic mass = (92.21×27.98)+(4.70×28.98)+(3.09×29.97) /100

Average atomic mass =  2580.04 +136.21+92.61 / 100

Average atomic mass = 2808.86 / 100

Average atomic mass  = 28.08amu.

The average atomic mass is closer to Si- 28 because this isotope is present in more percentage in the sample.

7 0
3 years ago
Read 2 more answers
True or false?
sertanlavr [38]
The answers are :
1 - F
2- T
5 0
2 years ago
Read 2 more answers
The cell theory was construted by​
NeTakaya

Answer:

Matthias Jakob Schleiden

Explanation:

The cell was initially discovered by Robert Hooke, but Schleiden developed the theory.

Hope this helps! :)

4 0
3 years ago
Which of the Atoms shown has an atomic number four
dimulka [17.4K]

Answer:

B

Explanation:

Atomic # = Protons

it says 4 p in the inside of the orbital

4 0
3 years ago
A marble rolls off horizontally from the edge of table top 1.50 m above the floor. it strikes the floor 2.0 m from the base of t
GrogVix [38]

a. t=0.553 s

b. vox(horizontal speed) = 3.62 m/s

<h3>Further explanation</h3>

Given

h = 1.5 m

x = 2 m

Required

a. time

b. vo=initial speed

Solution

Free fall motion

a. h = 1/2 gt²(vertical motion=h=voyt+1/2gt²⇒voy = 0)

\tt t=\sqrt{\dfrac{2h}{g} }

t = √2h/g

t = √2.1.5/9.8

t=0.553 s

b. x=vox.t(horizontal motion)

\tt x=v_{ox}\times t

vox=x/t

vox=2/0.553

vox=3.62 m/s

3 0
2 years ago
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