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3 years ago

5

Determine the velocity (in m/s) of the object during the first three seconds. Include a numerical answer accurate to the first d

ecimal place. If negative, include the - sign.

1 answer:

OlgaM077 [116]3 years ago

8 0

If it’s moved 3m in 3s then it should be 3m/s

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How many atoms are in a sample of 1.83 moles of potassium (K) atoms?

telo118 [61]

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</span>1.83 moles K (6.022 x 10^23 atoms / mole ) = 1.10 x 10^24 atoms K

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3 years ago

How does the wind turbine generator work?

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Answer: wind pushes directly against the blades of the turbine, which converts the linear motion of the wind into the rotary motion, then it spins the generator's rotor and the harder the wind pushes, the more electrical energy can be generated.

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3 years ago

The two forces of a 3rd law pair always act on different bodies. The two forces of a 3rd law pair always act on different bodies

svetoff [14.1K]

1. The two forces of a 3rd law pair always act on different bodies.

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SO above statement is TRUE because Newton's III law is valid for two different objects where one object will exert force and other body will exert reaction force on it.

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FALSE

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3. Part G According to Newton's 3rd law, the force on the (smaller) moon due to the (larger) earth is

(i) greater in magnitude and antiparallel to the force on the earth due to the moon.

(ii) greater in magnitude and parallel to the force on the earth due to the moon.

(iii) equal in magnitude but antiparallel to the force on the earth due to the moon.

(iv) equal in magnitude and parallel to the force on the earth due to the moon.

(v) smaller in magnitude and antiparallel to the force on the earth due to the moon.

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3 years ago

What average force is needed to accelerate a 7.00-gram pellet from rest to 155 m/s over a distance of 0.600 m along the barrel o

leonid [27]

Answer: The force needed is 140.22 Newtons.

Explanation:

The key assumption in this problem is that the acceleration is constant along the path of the barrel bringing the pellet from velocity 0 to 155 m/s. This means the velocity is linearly increasing in time.

The force exerted on the pellet is

F = m a

In order to calculate the acceleration, given the displacement d,

$d = \frac{1}{2}at^2\implies a=\frac{2d}{t^2}$

we will need to determine the time t it took for the pellet to make the distance through the barrel of 0.6m. That time can be determined using the average velocity of the pellet while traveling through the barrel. Since the velocity is a linear function of time, as mentioned above, the average is easy to calculate as:

$\overline{v}=\frac{1}{2}(v_{end}-v_{start})=\frac{1}{2}(155-0)\frac{m}{s}=77.5\frac{m}{s}$

This value can be used to determine the time for the pellet through the barrel:

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Finally, we can use the above to calculate the force:

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3 years ago

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Bogdan [553]

Answer: strength.

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3 years ago

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