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Anna [14]
3 years ago
12

How are sounds alike in the beginning

Physics
1 answer:
Otrada [13]3 years ago
7 0
They are alike because they both have vibrations to make sound
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How would you describe a solution?
liberstina [14]

Answer: A solution is the end of a task.

Explanation:

4 0
3 years ago
Find the range of a projectile launched at an angle of 30° with an initial velocity of 20m/s.​
Tems11 [23]

Answer:

<em>The range is 35.35 m</em>

Explanation:

<u>Projectile Motion</u>

It's the type of motion that experiences an object projected near the Earth's surface and moves along a curved path exclusively under the action of gravity.

Being vo the initial speed of the object, θ the initial launch angle, and g=9.8m/s^2 the acceleration of gravity, then the maximum horizontal distance traveled by the object (also called Range) is:

\displaystyle d={\frac  {v_o^{2}\sin(2\theta )}{g}}

The projectile was launched at an angle of θ=30° with an initial speed vo=20 m/s. Calculating the range:

\displaystyle d={\frac  {20^{2}\sin(2\cdot 30^\circ )}{9.8}}

\displaystyle d={\frac  {400\sin(60^\circ )}{9.8}}

d=35.35\ m

The range is 35.35 m

7 0
3 years ago
Dose scientists believe the earth four layers were fomed
horsena [70]
Yes because they believe they were formed from magma solidifying.
6 0
4 years ago
Part E<br> How does the motion of your finger along lines 1, 2, and 3 compare?
grigory [225]

Answer:

Can you explain this better?

Explanation:

3 0
3 years ago
Durante un intento juego de croquet, una bola de 0.52 kg en reposo sobre el cesped es golpeada por un mazo con una fuerza promed
Romashka [77]

Answer: 2.63 m/s

Explanation:

The question in english is written below:

During an attemp of croquet game, a 0.52 kg ball at rest on the grass is hit by a mallet with an average force of 190 N, if the mallet is in contact with the ball for 7.2(10)^{-3} s,  Whay is the speed of the ball just after being hit?

According to Newton's second law of motion, the force F exerted on an object is directly proportional to its mass m and acceleration a:

F=m.a (1)

On the other hand, acceleration is defined as the variation of velocity V in time t:

a=\frac{V}{t} (2)

Substituting (2) in (1):

F=m\frac{V}{t} (3)

Where:

F=190 N

m=0.52 kg

t=7.2(10)^{-3} s

Isolating the velocity V from (3):

V=\frac{Ft}{m} (4)

V=\frac{(190 N)(7.2(10)^{-3} s)}{0.52 kg}

Finally:

V=2.63 m/s

6 0
4 years ago
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