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Anna71 [15]
3 years ago
9

Simplify the radical expression. Leave it in radical form. SHOW YOUR WORK √75 + √3 √75 + √3

Mathematics
1 answer:
balandron [24]3 years ago
8 0
">" means results into or you can think about it as saying equals (=)
√75 = √5 * √15 > √5 * √5 * √3 > 5<span>√3
</span><span>√3
</span>√75 = √5 * √15 > √5 * √5 * √3 > 5√3
√3
Which then leads to..
5√3 + 5√3 + √3 + √3
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How many solutions does the linear equation have?
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Step-by-step explanation:

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Answer:

First, we know that:

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I can't know for sure what is the exact equation, so I will assume two cases.

The first case is if the equation is:

\frac{cot(x)}{sin(x)} - csc(x)

if we replace cot(x) and csc(x) we get:

\frac{cot(x)}{sin(x)} - csc(x) = \frac{cos(x)}{sin(x)} \frac{1}{sin(x)}  - \frac{1}{sin(x)}

Now let's we can rewrite this as:

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\frac{cos(x)}{sin^2(x)}  - \frac{sin(x)}{sin^2(x)} = \frac{cos(x) - sin(x)}{sin^2(x)}

We can't simplify it more.

Second case:

If the initial equation was

\frac{cot(x)}{sin(x) - csc(x)}

Then if we replace cot(x) and csc(x)

\frac{cos(x)}{sin(x)}*\frac{1}{sin(x) - 1/sin(x)} = \frac{cos(x)}{sin(x)}*\frac{1}{sin^2(x)/sin(x) - 1/sin(x)}

This is equal to:

\frac{cos(x)}{sin(x)}*\frac{sin(x)}{sin^2(x) - 1}

And we know that:

sin^2(x) + cos^2(x) = 1

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sin^2(x) - 1 = -cos^2(x)

So we can replace that in our equation:

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zhuklara [117]

Answer:

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