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2 years ago

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A school club has ordered a box of 50 booklets for a fundraiser. Unfortunately, 10 of the booklets are missing several pages. A

student randomly selects 5 booklets to hand out in class. What is the probability the student selects 5 booklets with no missing pages? Round the answer to the nearest whole percent 31% 40% 54% 58%

1 answer:

Airida [17]2 years ago

4 0

Answer:

50%

Step-by-step explanation:

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All the fourth-graders in a certain elementary school took a standardized test. A total of 85% of the students were found to be

Aneli [31]

Answer:

There is a 2% probability that the student is proficient in neither reading nor mathematics.

Step-by-step explanation:

We solve this problem building the Venn's diagram of these probabilities.

I am going to say that:

A is the probability that a student is proficient in reading

B is the probability that a student is proficient in mathematics.

C is the probability that a student is proficient in neither reading nor mathematics.

We have that:

$A = a + (A \cap B)$

In which a is the probability that a student is proficient in reading but not mathematics and $A \cap B$ is the probability that a student is proficient in both reading and mathematics.

By the same logic, we have that:

$B = b + (A \cap B)$

Either a student in proficient in at least one of reading or mathematics, or a student is proficient in neither of those. The sum of the probabilities of these events is decimal 1. So

$(A \cup B) + C = 1$

In which

$(A \cup B) = a + b + (A \cap B)$

65% were found to be proficient in both reading and mathematics.

This means that $A \cap B = 0.65$

78% were found to be proficient in mathematics

This means that $B = 0.78$

$B = b + (A \cap B)$

$0.78 = b + 0.65$

$b = 0.13$

85% of the students were found to be proficient in reading

This means that $A = 0.85$

$A = a + (A \cap B)$

$0.85 = a + 0.65$

$a = 0.20$

Proficient in at least one:

$(A \cup B) = a + b + (A \cap B) = 0.20 + 0.13 + 0.65 = 0.98$

What is the probability that the student is proficient in neither reading nor mathematics?

$(A \cup B) + C = 1$

$C = 1 - (A \cup B) = 1 - 0.98 = 0.02$

There is a 2% probability that the student is proficient in neither reading nor mathematics.

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3 years ago

Heyyy I need helppp plzzz

Alecsey [184]

Answer:

x + 2x = 109

Step-by-step explanation:

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3 years ago

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Which expression have the same value as the product of 2.7 and 4

Maurinko [17]

Answer:

Step-by-step explanation:

2.7*4=10.80

27*0.4=10.80 we multiplied 27 by 10 but divide 4 by 10

0.27*40=10.80

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3 years ago

POINTS Please HurryHassan helps his dad with newspaper deliveries. He gets $5 every morning and 10 cents for every paper deliver

dedylja [7]

Answer:

(20.60-5)/0.10=156 Papers

Step-by-step explanation:

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2 years ago

Read 2 more answers

I got the first two can you help me with the last one PLZ

Nat2105 [25]

1. Geometric Sequence

2. $a_n = a_{n-1} * 3$

3. $a_n = 6 * (3)^{n-1}$

Step-by-step explanation:

Given sequence is:

6, 18, 54, 162,....

Here

$a_1 =6\\a_2 = 18\\a_3 = 54$

(a) Is this an arithmetic or geometric sequence?

We can see that the difference between the terms is not same so it cannot be an arithmetic sequence.

We have to check for common ratio (ratio between consecutive terms of a sequence) denoted by r

$r = \frac{a_2}{a_1} = \frac{18}{6}= 3\\r = \frac{a_3}{a_2} = \frac{54}{18} = 3$

As the common ratio is same, the given sequence is a geometric sequence.

(b) How can you find the next number in the sequence?

Recursive formulas are used to find the next number in sequence using previous term

Recursive formula for a geometric sequence is given by:

$a_n = a_{n-1} * r$

In case of given sequence,

$a_n = a_{n-1} * 3$

So to find the 5th term

$a_5 = a_4*3\\a_5 = 162*3\\a_5 = 486$

(c) Give the rule you would use to find the 20th week.

In order to find the pushups for 20th week, explicit formul for sequence will be used.

The general form of explicit formula is given by:

$a_n = a_1 * r^{n-1}$

Putting the values of a_1 and r

$a_n = 6 * (3)^{n-1}$

Hence,

1. Geometric Sequence

2. $a_n = a_{n-1} * 3$

3. $a_n = 6 * (3)^{n-1}$

Keywords: Geometric sequence, common ratio

Learn more about geometric sequence at:

#LearnwithBrainly

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3 years ago