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Dafna11 [192]
3 years ago
8

A developer has requested permission to build a large retail store at a location adjacent to the intersection of an undivided fo

ur-lane major road and a two-lane minor road. Traffic on the minor road is controlled by a stop sign. The speed limits are 40 and 55 mi/h on the minor and major roads, respectively. The building is to be located at a distance of 70 ft from the near lane of one of the approaches of the minor road.
Determine where the building should be located relative to the centerline of the outside lane of the major road in order to provide adequate sight distance for a driver on the minor road to turn right onto the major road after stopping at the stop line. Design vehicle is a single-unit truck. Lanes on the major road are 12ft wide. Median width in the major road is 8ft and the approach grade on the minor road is 4%.

Engineering
1 answer:
stepladder [879]3 years ago
4 0

Answer:

Detailed solution is given below:

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  1. def median(l):
  2.    if(len(l) == 0):
  3.       return 0
  4.    else:
  5.        l.sort()
  6.        if(len(l)%2 == 0):
  7.            index = int(len(l)/2)
  8.            mid = (l[index-1] + l[index]) / 2
  9.        else:
  10.            mid = l[len(l)//2]  
  11.        return mid  
  12. def mode(l):
  13.    if(len(l)==0):
  14.        return 0
  15.    mode = max(set(l), key=l.count)
  16.    return mode  
  17. def mean(l):
  18.    if(len(l)==0):
  19.        return 0
  20.    sum = 0
  21.    for x in l:
  22.        sum += x
  23.    mean = sum / len(l)
  24.    return mean
  25. lst = [5, 7, 10, 11, 12, 12, 13, 15, 25, 30, 45, 61]
  26. print(mean(lst))
  27. print(median(lst))
  28. print(mode(lst))

Explanation:

Firstly, we create a median function (Line 1). This function will check if the the length of list is zero and also if it is an even number. If the length is zero (empty list), it return zero (Line 2-3). If it is an even number, it will calculate the median by summing up two middle index values and divide them by two (Line 6-8). Or if the length is an odd, it will simply take the middle index value and return it as output (Line 9-10).

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