Um.... I am confused I do not know what u are asking me.
I am so sorry that I can not help , but isf I knew it I would help.
Answer:
15.98
Step-by-step explanation:
∑₁¹⁰ 
![=8[1+\frac{1}{4} +\frac{1}{16} + ........ +t_{10}]](https://tex.z-dn.net/?f=%3D8%5B1%2B%5Cfrac%7B1%7D%7B4%7D%20%2B%5Cfrac%7B1%7D%7B16%7D%20%2B%20........%20%2Bt_%7B10%7D%5D)
We have to use the formula of sum of a G.P. series with common ratio r < 1.
If the first term is a, the common ratio is r and the number of terms is n then the sum [a + ar + ar² + ar³ + ......... up to n terms] is given by
![[a \times\frac{1-r^{n} }{1-r}]](https://tex.z-dn.net/?f=%5Ba%20%5Ctimes%5Cfrac%7B1-r%5E%7Bn%7D%20%7D%7B1-r%7D%5D)
![= 8[1 \times \frac{1-\frac{1}{2^{10} } }{1-\frac{1}{2} } ]](https://tex.z-dn.net/?f=%3D%208%5B1%20%5Ctimes%20%5Cfrac%7B1-%5Cfrac%7B1%7D%7B2%5E%7B10%7D%20%7D%20%7D%7B1-%5Cfrac%7B1%7D%7B2%7D%20%7D%20%5D)
(Answer)
Answer:
E=-24
Step-by-step explanation:
Answer:
option B
(−1, 0) and (0, 6)
Step-by-step explanation:
Given in the question two equations,
Equation 1
y =−x² + 5x + 6
Equation 2
−6x + y = 6
plug value of y in second equation
−6x −x² + 5x + 6 = 6
-x² -6x + 5x +6 - 6 = 0
-x² - x + 0 = 0
-x² -x = 0
-x(x+1) = 0
x = 0
and
x = -1
plug value of x in second equation to find y
x = 0
−6(0) + y = 6
0 + y = 6
y = 6
and
x = -1
−6(-1) + y = 6
6 + y = 6
y = 0
<span>3t<-15 solve for t
divide both sides by 3
3t/3 < -15/3
Simplify
t < -5
Anser is </span><span>a. t<-5</span>
