Thus L.H.S = R.H.S that is 2/√3cosx + sinx = sec(Π/6-x) is proved
We have to prove that
2/√3cosx + sinx = sec(Π/6-x)
To prove this we will solve the right-hand side of the equation which is
R.H.S = sec(Π/6-x)
= 1/cos(Π/6-x)
[As secƟ = 1/cosƟ)
= 1/[cos Π/6cosx + sin Π/6sinx]
[As cos (X-Y) = cosXcosY + sinXsinY , which is a trigonometry identity where X = Π/6 and Y = x]
= 1/[√3/2cosx + 1/2sinx]
= 1/(√3cosx + sinx]/2
= 2/√3cosx + sinx
R.H.S = L.H.S
Hence 2/√3cosx + sinx = sec(Π/6-x) is proved
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Answer:
33.3
Step-by-step explanation:
Answer: Hello your question is missing some details but I will provide a general solution based on the scope of the problem and you can plugin the missing value
answer = Volume of rectangular prism box / volume of cube
Step-by-step explanation:
To determine the number of Dice that will fit in the rectangular prism box
First : calculate the volume of the cube box ( dice )
volume of a Cube box : V = L^3 where L = side length
next : calculate the volume of the rectangular prism box
volume of rectangular prism box = L * b * h
L= length , b = width , h = height
final step : Divide the volume of the rectangular prism box by the volume of the cube box ( dice )
= ( L * b * h ) / ( L^3 )
