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3 years ago

What is the formula for diboron dioxide

Chemistry

1 answer:

Vaselesa [24]3 years ago

7 0

Answer:

B2O3

Explanation:

good luck have a nice day

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Answer:

112.

a. [Ne] 3 $s^{2}$ 3 $p^{5}$

b. [He] 2 $s^{2}$ 2 $p^{1}$

c. [Ar] 3 $d^{1}$ 4 $s^{2}$

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3 years ago

Read 2 more answers

Lithium (Li) and oxygen (O) are both in period 2. They both have _____.

AlladinOne [14]

They both have two electron shells

<h3>Further explanation</h3>

The period 2 element lies in the second row of the periodic system.

Consists of the elements: lithium, beryllium, boron, carbon, nitrogen, oxygen, fluorine, and neon

Lithium (Li)

atomic number : 3

electron configuration : [He] 2s¹

atomic number = number of proton=number of electron(in neutral atom)

So Li have 3 protons and 3 electrons

Because it fills the 2s orbital it has 2 shells

Oxygen (O)

atomic number : 8

electron configuration : [He] 2s²2p⁴

So O have 8 protons and 8 electrons

Because it fills the 2s and 2p orbital it has 2 shells

So Lithium (Li) and Oxygen (O) are both have two electron shells

6 0

3 years ago

What is the solubility (in g/L) of calcium fluoride at 25°C? The solubility product constant for calcium fluoride is 3.4 × 10–11

PilotLPTM [1.2K]

<u>Answer:</u> The correct answer is Option b.

<u>Explanation:</u>

The balanced equilibrium reaction for the ionization of calcium fluoride follows:

$CaF_2\rightleftharpoons Ca^{2+}+2F^-$

s 2s

The expression for solubility constant for this reaction will be:

$K_{sp}=[Ca^{2+}][F^-]^2$

We are given:

$K_{sp}=3.4\times 10^{-11}$

Putting values in above equation, we get:

$3.4\times 10^{-11}=(s)\times (2s)^2\\\\3.4\times 10^{-11}=4s^3\\\\s=2.04\times 10^{-4}mol/L$

To calculate the solubility in g/L, we will multiply the calculated solubility with the molar mass of calcium fluoride:

Molar mass of calcium fluoride = 78 g/mol

Multiplying the solubility product, we get:

$s=2.04\times 10^{-4}mol/L\times 78g/mol=159.12\times 10^{-4}g/L=0.015g/L$

Hence, the correct answer is Option b.

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3 years ago