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3 years ago

3. What is the gram-formula mass of (NH4)3PO4?

1 answer:

4 0

The gram-formula mass means that the mass of one mole molecule. Then you just need to calculate the elements together. So the gram-formula mass of (NH4)3PO4 is equals to (14+4)*3+31+16*4= 149g/mol. So the answer is (c)

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You have 16.0 g of some compound and you perform an experiment to remove all of the oxygen, 11.2 g of iron is left. What is the

Makovka662 [10]

The empirical formula of this compound is $Fe_2O_3$

<h3>Empirical formula </h3>

To calculate the empirical formula of a compound, the value of moles of each element is needed.

As we have the information of the mass value, we will use the molar mass expression, which corresponds to:

$MM_O = 16g/mol\\MM_Fe = 55.8g/mol$

$MM = \frac{m}{mol}$

$16 = \frac{4.8}{x}$

$x = 0.3mol$

$55.8=\frac{11.2}{x}\\x = 0.2$

As the value of the empirical formula must be an integer, simply multiply the two values by a common factor:

$O = 0.3 \times 10 = 3\\Fe = 0.2 \times 10 = 2$

$Fe_2O_3$

So, the empirical formula of this compound is $Fe_2O_3$ .

Learn more about empirical formula: brainly.com/question/1247523

3 0

2 years ago

Atom A emits mainly X rays when it is excited. Atom B emits mainly gamma rays. Which emission corresponds to a transition betwee

Alex777 [14]

Hello,

They both emits mainly gamma rays. Which makes the emission a transition between the levels!

3 0

3 years ago

Read 2 more answers

A balloon of air occupies 10.0L(V2)at25.0°C(T2)and1.00atm(P2). What temperature (T1) was it initially, if it occupied 9.40 L (V1

andrey2020 [161]

Answer: The initial temperature was 263 K

Explanation:

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$

where,

$P_1$ = initial pressure of gas = 0.939 atm

$P_2$ = final pressure of gas = 1.00 atm

$V_1$ = initial volume of gas = 9.40 L

$V_2$ = final volume of gas = 10.0 L

$T_1$ = initial temperature of gas = ?

$T_2$ = final temperature of gas = $25^oC=273+25=298K$

Now put all the given values in the above equation, we get:

$\frac{0.939\times 9.40}{T_1}=\frac{1.00\times 10.0}{298}$

$T_1=263K$

Thus the initial temperature was 263 K

4 0

3 years ago

The graph shows the distribution of energy in the particles of two gas samples at different temperatures, T1 and T2. A, B, and C

soldi70 [24.7K]

Based on the information given regarding the energy, the true statement is C. "The number of particles able to undergo a chemical reaction is less than the number that is not able to."

<h3>What is energy?</h3>

It should be noted that energy is the quantitative property that must be transferred to a body to perform work on the body.

In this case, the graph is shown with two inverted graph curves running close to each other, and one of the curves labeled T1 is slightly more spread out than the other labeled T2.

Here, T1 is the only sample with a particle able to react. Particle B is more likely to participate in the reaction than particle A and the number of particles able to undergo a chemical reaction is less than the number that is not able to.

Learn more about energy on:

brainly.com/question/582060

6 0

3 years ago

How much energy is absorbed when a 50.0 gram magnesium strip is heated from 45 degrees to 90 degrees

Leno4ka [110]

Quantity of heat energy required for change of phase= (mass) x (heat of fusion or heat of vaporization), or in equation form Q=mL. Heat of fusion=80cal/g; heat of vaporization=540 cal/g
quanity of heat energy responsible for a temperature change= (mass) x (specific heat) x (change in temperature), or in equation form, Q=mcT

Here's another way to calculate it

Calculate the energy absorbed by 20 grams of 100 C water that is turned into 100 C steam
Q=(20g)(540 cal/g)=10,800 cal

I hope this helps you.

7 0

3 years ago