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tester [92]
4 years ago
7

Which is true about the total mechanical energy in a closed system?

Chemistry
2 answers:
quester [9]4 years ago
4 0

Answer:

I believe that is C due to it being in a closed system

ryzh [129]4 years ago
3 0
It’s between C and B
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Radium decays to form radon. Which equation correctly describes this decay?<br><br> its D
netineya [11]

Answer:

The equation that correctly describes the decay is :

\frac{226}{88}Ra -----> \frac{222}{86}Rn + \frac{4}{2}He

Explanation:

When the solid radium start decaying in order to form the radon gas, it starts losing two protons with one neutron. The two neutron as well as one proton together forms an alpha particle, hence a type of radiation is formed. Also we know that radon itself is radioactive as it also leads to the decay, after that it loses an alpha particle and also form an element called as polonium. Radium being the most stable form of isotope, radium 226, also holds a half life of 1600 years. It will decay into radon 222 through the alpha decay or can also lead 212 by ejecting a carbon 14 nucleus.

4 0
3 years ago
Read 2 more answers
When a substance experiences a phase change it is still the same substance, just in a different form. True of or false
forsale [732]
True because its still technically the same substance
8 0
4 years ago
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What is a titration?​
BARSIC [14]

Answer:

titration is the slow addition of one solution of a known concentration to a known volume of another solution of unknown concentration until the reaction reaches neutralization which is often indicated by a color change.

Explanation:

look at the answer.

3 0
3 years ago
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Tellurium has eight isotopes: Te-120 (0.09%), Te-122 (2.46%), Te-123 (0.87%), Te-124 (4.61%), Te-125 (6.99%), Te-126 (18.71%), T
Elena-2011 [213]

The average atomic mass of tellurium, calculated from its eight isotopes (Te-120 (0.09%), Te-122 (2.46%), Te-123 (0.87%), Te-124 (4.61%), Te-125 (6.99%), Te-126 (18.71%), Te-128 (31.79%), and Te-130 (34.48%)) is 127.723 amu.

The average atomic mass of Te can be calculated as follows:

A = m_{Te-120}\%_{Te-120} + m_{Te-122}\%_{Te-122} + m_{Te-123}\%_{Te-123} + m_{Te-124}\%_{Te-124} + m_{Te-125}\%_{Te-125} + m_{Te-126}\%_{Te-126} + m_{Te-128}\%_{Te-128} + m_{Te-130}\%_{Te-130}

Where:

m: is the mass

%: is the abundance percent

Knowing all the masses and abundance values, we have:

A = 120*0.09\% + 122*2.46\% + 123*0.87\% + 124*4.61\% + 125*6.99\% + 126*18.71\% + 128*31.79\% + 130*34.48\%

To find the <u>average atomic mass</u> we need to change all the <u>percent values</u> to <u>decimal ones</u>

A = 120*9 \cdot 10^{-4} + 122*2.46 \cdot 10^{-2} + 123*8.7\cdot 10^{-3} + 124*4.61 \cdot 10^{-2} + 125*6.99\cdot 10^{-2} + 126*0.1871 + 128*0.3179 + 130*0.3448 = 127.723

Therefore, the average atomic mass of tellurium is 127.723 amu.

You can find more about average atomic mass here brainly.com/question/11096711?referrer=searchResults

I hope it helps you!

4 0
3 years ago
A person has a mass of 63.4 kg .what is that weight in pound
miv72 [106K]

Answer:

140 lb  

Explanation:

\text{Mass} = \text{63.4 kg} \times \dfrac{\text{2.205 lb}}{\text{1 kg}} = \textbf{140 lb}

4 0
3 years ago
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