Please help me please

5) Mario owns a plumbing business. He charges an hourly rate plus a onetime set up fee. His first job was 4 hours and he charged

Wittaler [7]

Answer:

Results are below.

Step-by-step explanation:

First, we need to calculate the variable income per job:

First job= 450 - 150= 300

Second job= 675 - 150= 525

Now, the hourly rate:

Hourly rate= total variable income / number of hours

First job= 300 / 4= $75

Second job= 525 / 3= $175

It is probably that the second job was 7 hours long. If not, he doesn't charge the same amount per hour

5 0

3 years ago

Consider the exponential function

evablogger [386]

Given:

The given function $f(x)=19,000 \cdot 0.96 ^x$ which models the value of Mark’s car, where x represents the number of years since he purchased the car.

We need to determine the approximate value of Mark's car after 7 years.

Value of the car:

The value of the car after 7 years can be determined by substituting x = 7 in the function $f(x)=19,000 \cdot 0.96 ^x$ , we get;

$f(7)=19,000 \cdot 0.96 ^7$

$f(7)=19,000 \cdot 0.7514474781$

$f(7)=14277.502$

Rounding off to the nearest dollar, we get;

$f(7)=14278$

Thus, the approximate value of Mark's car after 7 years is $14278.

Hence, Option a is the correct answer.

7 0

3 years ago

Read 2 more answers

Match the numerical expressions to their simplest forms.

Aloiza [94]

Answer:

$(a^6b^1^2)^\frac{1}{3}$ = $a^2b^4$

$\frac{(a^5b^3)^\frac{1}{2}}{(ab)^-^\frac{1}{2}}$ = $a^3b^2$

$(\frac{a^5}{a^-^3b^-^4})^\frac{1}{4}$ = $a^2b$

$(\frac{a^3}{ab^-^6})^\frac{1}{2}$ = $ab^3$

Step-by-step explanation:

Simplify each of the expressions:

1

$(a^6b^1^2)^\frac{1}{3}$

Distribute the exponent. Multiply the exponent of the term outside of the parenthesis by the exponents of the variable.

$(a^6b^1^2)^\frac{1}{3}$

$a^6^*^\frac{1}{3}b^1^2^*^\frac{1}{3}$

Simplify,

$a^2b^4$

2

Use a similar technique to solve this problem. Remember, a fractional exponent is the same as a radical, if the denominator is (2), then the operation is taking the square root of the number.

$\frac{(a^5b^3)^\frac{1}{2}}{(ab)^-^\frac{1}{2}}$

Rewrite as square roots:

$\frac{\sqrt{a^5b^3}}{\sqrt{(ab)}^-^1}$

A negative exponent indicates one needs to take the reciprocal of the number. Apply this here:

$\frac{\sqrt{a^5b^3}}{\frac{1}{\sqrt{ab}}}$

Simplify,

$\sqrt{a^5b^3}*\sqrt{ab}$

Since both numbers are under a radical, one can rewrite them such that they are under the same radical,

$\sqrt{a^5b^3*ab}$

Simplify,

$\sqrt{a^6b^4}$

Since this operation is taking the square root, divide the exponents in half to do this operation:

$a^3b^2$

3

$(\frac{a^5}{a^-^3b^-^4})^\frac{1}{4}$

Simplify, to simplify the expression in the numerator and the denominator, the base must be the same. Remember, the base is the number that is being raised to the exponent. One subtracts the exponent of the number in the denominator from the exponent of the like base in the numerator. This only works if all terms in both the numerator and the denominator have the operation of multiplication between them:

$(\frac{a^8}{b^-^4})^\frac{1}{4}$

Bring the negative exponent to the numerator. Change the sign of the exponent and rewrite it in the numerator,

$(a^8b^4)^\frac{1}{4}$

This expression to the power of the one forth. This is the same as taking the quartic root of the expression. Rewrite the expression with such,

$\sqrt[4]{a^8b^4}$

SImplify, divide the exponents by (4) to simulate taking the quartic root,

$a^2b$

4

$(\frac{a^3}{ab^-^6})^\frac{1}{2}$

Using all of the rules mentioned above, simplify the fraction. The only operation happening between the numbers in both the numerator and the denominator is multiplication. Therefore, one can subtract the exponents of the terms with the like base. The term in the denomaintor can be rewritten in the numerator with its exponent times negative (1).

$(a^3^-^1b^(^-^6^*^(^-^1^)^))^\frac{1}{2}$