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trasher [3.6K]
3 years ago
9

Guys I need your HELP ASAPP!!!!!

Mathematics
1 answer:
Genrish500 [490]3 years ago
5 0

Answer:

HOPE THAT WAS TRUE

Step-by-step explanation:

- 3 +  \sqrt{m + 59}  = m \\   \sqrt{m + 59}  = m + 3 \\  {(m + 59)}^{ \frac{1}{2} }  = m + 3 \\  \frac{1}{2}  log(m + 59)  =  log(m + 3)  \\ 0.5 log(m)  + 0.5 log(59) = log(m)+log(3)  \\ 0.5 log(m)  = 0.5 log(59)  -  log(3)  \\

0.5 log(m)  = 0.885 - 0.477 \\ 0.5 log(m)  = 0.408 \\  log(m)  = 0.816

m =  {10}^{0.816}  = 6.556

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Given the following function, find f(-2), f(0), and f(4).
borishaifa [10]

Answer:

f(-2) = 0

f(0) = -4

f(4) = 12

Step-by-step explanation:

Given the function f(x) = x^2 - 4, we must plug in the values substituting x for each of the answers.

f(-2) = (-2)^2 - 4

-2 times itself is a positive 4, therefore:

f(-2) = 4 - 4

f(-2) = 0

We do the same for each answer.

f(0) = (0)^2 - 4

f(0) = -4

f(4) = (4)^2 - 4

f(4) = 16 - 4

f(4) = 12

6 0
3 years ago
What is the value of the expression when a = 5 and b = 2? 2a+b−3 A.6 B.9 C.11 D.24
Studentka2010 [4]

2a + b - 3

2(5) + 2 - 3

10 + 2 - 3

12 - 3 = 9

Answer - 9

Hope this Helps!!

6 0
3 years ago
Read 2 more answers
Answer the following True or False:
Ilia_Sergeevich [38]

False; consider as a counterexample the function <em>f</em> : ℝ→ℝ defined by

f(x)=\begin{cases}-3&\text{for }x\neq2\\0&\text{for }x=2\end{cases}

Clearly <em>f</em> approaches -3 as <em>x</em> gets closer to -2, but neither limit from either side is equal to the function's value at <em>x</em> = 2 (that is, -3 ≠ 0), so <em>f</em> is not continuous.

4 0
3 years ago
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Answer:

which of the following element is essential to formation and

Step-by-step explanation:

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2 years ago
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Answer:

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Step-by-step explanation:

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8 0
3 years ago
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