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harkovskaia [24]
3 years ago
8

Please help I need help on this thank you

Mathematics
1 answer:
Charra [1.4K]3 years ago
8 0
IJ because I learned this
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I'm an integer. I am less than zero but greater than -13. When you subtract me from -11. The result is positive. What number am
harina [27]

<u>Answer</u><u>: </u>

Required integer is -12.

Step-by-step explanation:

Given:

Required number is integer.

Required integer is less than zero

greater than -13.

When number is substracted from -11, result is positive.

To Find:

The integer=?

Solution:

Lets assume required integer = x

As Required integer is less than zero and greater than -13 ,  

-13 < x < 0     ------(1)

Also when number is subtracted from -11, result is positive.  

=>  -11 – x > 0

=> -11 > x   -------(2)  

So form 1 and 2  

-13 < x < -11 that is x is an integer which is less than -11 and greater than -13.  There is only one integer between -13 and -11 that is -12.

Hence required integer is -12.

4 0
3 years ago
Clare subscribes to an online music streaming service
xeze [42]

Answer:

She should go with service 2 because it is, cheaper. Service 1 cost $107.52, but service 2 cost only $105.

Step-by-step explanation:

Cost now+increase$=new cost

(Part=percent*whole)

Increase=percent increase*cost now

i=12%*$96

i=0.12*96=$11.52

$96+11.52=107.52

Service two⬇️

8.72*12=$105

5 0
3 years ago
Can someone please help?
Ber [7]

Answer:

  (B)  26°

Step-by-step explanation:

The angle at A made by the radius and the tangent is 90°. The angle at O is the same as arc AB, 64°. The acute angles in a right triangle are complementary, so the angle at C is the complement of 64°.

∠ACB = 90° -64°

∠ACB = 26°

5 0
3 years ago
Convert the polar coordinates (-3, -60°) to Cartesian coordinates.
notsponge [240]

Answer:

(1.5,-2.6)

Step-by-step explanation:

Given the polar coordinates (-3,60°).

Let our Cartesian coordinates be (x,y)

#We know that when converting the rectangular coordinates (x,y) to polar (r,θ), then:

r=\sqrt{x^2+y^2}\\\\\therefore r^2=x^2+y^2\\\\\theta=tan^{-1}(y/x)\\\therefore tan \theta=y/x

#Using the illustration above, we can express our polar coordinates as:

-3=\sqrt{x^2+y^2}\\\\-60\textdegree=tan^{-1}(y/x}

#Solve simultaneously to solve for x and y:

(-3)^2=x^2+y^2\ \ \ \ \ \ \ \ \ \ i\\\\tan(-0\texdegree)=y/x\ \ \ \ \ \ \ \ ...ii\\\\y=x\ tan(-60\textdegree)\ \ \ \ \ \ \ ...iii\\\\\#substitute\  y \ in\  i\\\\(-3)^2=x^2+(x \ tan (-60\textdegree))^2\\\\9=x^2+3x^2\\\\x=\sqrt{9/4}=1.5\\\\y=1.5\ tan(-60\textdegree)=-2.5981\approx-2.6

Hence, the Cartesian coordinates are (1.5,-2.6)

6 0
3 years ago
Need answer please!!!!!!
patriot [66]
Answer is D i’m sure but unit test don’t matter as much so don’t stress
7 0
3 years ago
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