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vaieri [72.5K]
3 years ago
6

Help me solve this problem please

Mathematics
1 answer:
allochka39001 [22]3 years ago
6 0

Answer:

Step-by-step explanation:

4^2+x^2 = 15^2

x^2 = 15^2 - 4^2 = 225-16 = 209

x=sqrt(209)

x = 14.46

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Answer:

Figures A,D are polygons.

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If N is the population of the colony and t is the time in​ days, express N as a function of t. Consider Upper N 0 is the origina
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Answer:

(a)N(t)=Noe^{kt}

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(c)5 days

Step-by-step explanation:

(a)Given an original amount N_o at t=0. The population of the colony with a growth rate k \neq 0, where k is a constant is given as:

N(t)=Noe^{kt}

(b)If N_o=1000 and the population after 1 day, N(1)=1800

Then, from our model:

N(1)=1800

1800=1000e^{k}\\$Divide both sides by 1000\\e^{k}=1.8\\$Take the natural logarithm of both sides\\k=ln(1.8)

Therefore, our model is:

N(t)=1000e^{t*ln(1.8)}\\N(t)=1000\cdot1.8^t

In 3 days time

N(3)=1000\cdot1.8^3=5832

The population of mosquitoes in 3 days time will be approximately 5832.

(c)If the population N(t)=20,000,we want to determine how many days it takes to attain that value.

From our model

N(t)=1000\cdot1.8^t\\20000=1000\cdot1.8^t\\$Divide both sides by 1000\\20=1.8^t\\$Convert to logarithm form\\Log_{1.8}20=t\\\frac{Log 20}{Log 1.8}=t\\ t=5.097\approx 5\; days

In approximately 5 days, the population of mosquitoes will be 20,000.

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