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2 years ago

Help me solve this problem please

Mathematics

1 answer:

allochka39001 [22]2 years ago

6 0

Answer:

Step-by-step explanation:

4^2+x^2 = 15^2

x^2 = 15^2 - 4^2 = 225-16 = 209

x=sqrt(209)

x = 14.46

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Find r if 0=pi/6 rad sector 64m^2

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Given:

Area of a sector = 64 m²

The central angle is $\theta=\dfrac{\pi}{6}$ .

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The radius or the value of r.

Solution:

Area of a sector is:

$A=\dfrac{1}{2}r^2\theta$

Where, r is the radius of the circle and $\theta$ is the central angle of the sector in radian.

Putting $A=64,\theta=\dfrac{\pi}{6}$ , we get

$64=\dfrac{1}{2}r^2\times \dfrac{\pi}{6}$

$64=\dfrac{\pi}{12}r^2$

$64\times \dfrac{12}{\pi}=r^2$

$\dfrac{768}{\pi}=r^2$

Taking square root on both sides, we get

$\sqrt{\dfrac{768}{\pi}}=r$

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