Answer:
A(t) = amount remaining in t years
= A0ekt, where A0 is the initial amount and k is a constant to be determined.
Since A(1690) = (1/2)A0 and A0 = 80,
we have 40 = 80e1690k
1/2 = e1690k
ln(1/2) = 1690k
k = -0.0004
So, A(t) = 80e-0.0004t
Therefore, A(430) = 80e-0.0004(430)
= 80e-0.172
≈ 67.4 g
Step-by-step explanation:
Factor out the GCF of
21
b
2
c
2
from
63
b
2
c
4
+
42
b
3
c
2
.
Tap for fewer steps...
Factor out the GCF of
21
b
2
c
2
from each term in the polynomial.
Tap for fewer steps...
Factor out the GCF of
21
b
2
c
2
from the expression
63
b
2
c
4
.
21
b
2
c
2
(
3
c
2
)
+
42
b
3
c
2
Factor out the GCF of
21
b
2
c
2
from the expression
42
b
3
c
2
.
21
b
2
c
2
(
3
c
2
)
+
21
b
2
c
2
(
2
b
)
Since all the terms share a common factor of
21
b
2
c
2
, it can be factored out of each term.
21
b
2
c
2
(
3
c
2
+
2
b
)
The greatest common factor
GCF
is the term in front of the factored expression.
21
b
2
c
2
A total of 5+6 for the total deduction so 11$. Her savings account has a total of -11$ since Monday as another way of phrasing it
Answer:-18 and T=3+Y
Step-by-step explanation:
No, you would do 100 - 64 because 10^2 is 100 and 8^2 is 64.
100-64= 36
The square root of 36 is 6. The length of the other leg is 6.
