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4 years ago

Solve with quadratic formula or factor square 2x to the 2nd power -x =3

Mathematics

1 answer:

BabaBlast [244]4 years ago

4 0

Answer:

Step-by-step explanation:

2x²-2x=3

2x²-2x -3 = 0

note :

the discriminat of each quadratic equation : ax²+bx+c=0 ....(a ≠ 0) is :

Δ = b² -4ac

1 ) Δ > 0 the equation has two reals solutions : x = (-b±√Δ)/2a

2 ) Δ = 0 : one solution : x = -b/2a

3 ) Δ < 0 : no reals solutions

***** in this exercice : a = 2 b = -2 c = -3

Δ = (-2)² -4(2)(-3) =28

x = (2±√28)/6

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slavikrds [6]

maybe: Mean

2.22

Median =

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Explanation:

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Median: First we put the numbers in order from lowest to highest:

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3 years ago

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Find the equation of a line in slope intercept form that is perpendicular to the line y = 2x + 6 through the point (10,4)

dalvyx [7]

The equation of the straight line is y = -1/6(x - 10) + 4

<h3>How to determine the line equation?</h3>

The equation is given as:

y = 2x + 6

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Where:

Slope = m

So, we have:

m = 6

The slopes of perpendicular lines are represented as:

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So, we have:

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The equation is then represented as:

y = n(x - x1) + y1

This gives

y = -1/6(x - 10) + 4

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2 years ago

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4 years ago

Given that the points (-1,6). (3,6), (3, 1), and (-1, 1) are vertices of a rectangle, how much shorter is the width than the len

Ksju [112]

Since the given coordinates are already in order,
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Using distance formula,
$\sqrt{ {( - 1 - 3)}^{2} + {(6 - 6)}^{2} } \\ = \sqrt{ { (- 4)}^{2} } \\ = \sqrt{16 } \\ = 4$
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Applying this again on 2nd and 3rd coordinates,
$\sqrt{ {(3 - 3)}^{2} + {(6 - 1)}^{2} } \\ = \sqrt{ {5}^{2} } \\ = 5$
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Since length's always gotta be greater than bredth
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Hence width is 1 unit shorter than length.

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4 years ago

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Olenka [21]

Answer:

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