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blagie [28]
3 years ago
12

Jim has to travel 3 kilometers to meet his friend. From his friend's house, Jim walks to the gym, which is 100 meters farther do

wn the road. What is the total distance that Jim traveled? A. 3.01 kilometers B. 3.1 kilometers C. 103 kilometers D. 13 kilometers
Mathematics
2 answers:
AVprozaik [17]3 years ago
4 0

Answer:

3.1 kilometers

Step-by-step explanation:

Mark me as brainliest if this helps!

REY [17]3 years ago
4 0

Answer:the total distance that Jim traveled is 3.1 kilometers.

Step-by-step explanation:

The total distance that Jim has to travel to meet her friend is 3 kilometers.

From his friend's house, Jim walks to the gym, which is 100 meters farther down the road. We would convert 100 meters to kilometers.

Recall: 1000 meters = 1 kilometer.

Therefore 100 meters = 100/1000 = 0.1 kilometers.

Therefore, the total distance that Jim traveled would be

3 + 0.1 = 3.1 kilometers

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We do what's in the parenthesis first.

9+9(2+4)÷3-2.

2+4=6.

Now our problem looks like this;

9+9(6)÷3-2 
OR
9+9×6÷3-2.

Anything in a parenthesis with no sign next to it, like this; 8(2), just means multiplication, so it would look like this: 8×2.

Next, we do all the multiplication in our problem.

9+9×6÷3-2.

9×6=54.

Now our problem looks like this;

9+54÷3-2.

Next, we do the division. 

9+54÷3-2

54÷3=18.

Now our problem looks like this;

9+18-2.

Next, we do the addition.

9+18-2

9+18=27

Now it looks like this;

27-2.

Finally, we subtract.

27-2=25.

Your final answer is 25!

Have a nice day! :)
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Answer:

Step-by-step explanation:

Given expression is,

\text{cot}A=\frac{1}{2}(\text{cot}\frac{A}{2}-\text{tan}\frac{A}{2})

To prove this identity we will take the right side of the identity,

\frac{1}{2}(\text{cot}\frac{A}{2}-\text{tan}\frac{A}{2})=\frac{1}{2}(\frac{1}{\text{tan}\frac{A}{2}}-tan\frac{A}{2})

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