Question

Solve the triangle with the law of sines

Answer 1

Answer:

Given:- m∠C = 73°, BC = 52units, m∠A = 93°, m∠B = 14°.

Using sine law,

B/sin(14°) = 52/sin(93°)

• B = 52 × sin(14°)/sin(93°)
• B = 12.6

C/sin(73°) = 52/sin(93°)

• C = 52 × sin(73°)/sin(93°)
• C = 49.8

Answer 2

Answer:

AC = 12.6

AB = 49.8

C = 73°

Step-by-step explanation:

(B/sin(14)) = (52/sin(93))

B = (52*sin(14))/sin(93)

B = 12.6

(C/sin(73)) = (52/sin(93))

C = (52*sin(73))/sin(93)

C = 49.8