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Vadim26 [7]
3 years ago
8

What is the perpendicular bisector of RT

Mathematics
1 answer:
Solnce55 [7]3 years ago
3 0
The perpendicular bisector of RT is B. SU.
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PLS HELP NEED DESPERATELY ALL WORK SHOWN PLS
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Answer:

yes

Step-by-step explanation:

yes

5 0
3 years ago
Find the leg of each isosceles right triangle when the hypotenuse is 5 square root 6
kozerog [31]
Hypotenuse = 5√6

Let the length of each leg be x, since it is Isosceles .

x² + x² = (5√6)²

2x² = (5 * 5 * √6 * √6)

2x² = 150

x² = 150/2

x² = 75

x = √75

x = √(25 * 3)

x = √25 * √3

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3 years ago
A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by th
olchik [2.2K]

Answer:

14.52 seconds.

Step-by-step explanation:

We have been given that the height of the rocket, y in feet, is related to the time after launch, x in seconds, by the given equation y=-16x^2+224x+121. We are asked to find the time, when the rocket will hit the ground.

We know that the rocket will hit the ground, when height will be 0. So to find the time when rocket will hit the ground, we will substitute y=0 in our given equation as:

0=-16x^2+224x+121

Let us solve for x using quadratic formula.

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

x=\frac{-224\pm\sqrt{224^2-4(-16)(121)}}{2(-16)}

x=\frac{-224\pm\sqrt{50176+7744}}{-32}

x=\frac{-224\pm\sqrt{57920}}{-32}

x=\frac{-224\pm240.66574}{-32}

x=\frac{-224+240.66574}{-32}, x=\frac{-224-240.66574}{-32}

x=\frac{16.66574}{-32}, x=\frac{-464.66574}{-32}

x=-0.520804375, x=14.520804375

Upon rounding to nearest 100th of second, we will get:

x\approx -0.52, x\approx 14.52

Since time cannot be negative, therefore, the rocket will hit the ground after 14.52 seconds.

6 0
3 years ago
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What is the approximate rate of change in the total calories Leo burned between 40 and 70 minutes?
Contact [7]

Answer:

Is that the second part of the question? Cuz dat dont make no sense

Im Leo lm.ao

8 0
3 years ago
Please help i don’t really understand this
Andrew [12]

Answer:

g(x) = 1/2x^2

Step-by-step explanation:

6 0
3 years ago
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