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iris [78.8K]
1 year ago
6

Find the area of the shaded sector of a circle. Leave ur answer in terms of pi

Mathematics
1 answer:
laila [671]1 year ago
6 0

The area of the shaded sector of a circle is 64 pie cm^2

Here we are given that there is a circle: whose radius is 16cm and the angle formed by two radius that is angle of the sector is 90.

The area of the sector of circle is basically the area of the arc of a circle.

The two combination of two radii forms the sector of a circle while the arc is in between these two radii.

Area of sector is given by:

Area of sector=\frac{mXY}{360^{0} }.лr^{2}

Substituting the given value in the formula of area of sector:

Area of sector is=\frac{90}{360}\times pie\times r^{2}

We get after solving,

Area of sector= 64 pie cm^2

So from the given options, option 4 is correct.

Hence the area of the sector is 64 pie cm^2

To know more about Area of the sector:

brainly.com/question/22972014

#SPJ9

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A marketing researcher wants to find a 96% confidence interval for the mean amount those visitors spend per person per day while
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Answer:

n=(\frac{2.054(12)}{4})^2 =37.97 \approx 38

So then the minimum sample to ensure the condition given is n= 38

Step-by-step explanation:

Notation

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)

\sigma=12 represent the population standard deviation

n represent the sample size  

ME = 4 the margin of error desired

Solution to the problem

When we create a confidence interval for the mean the margin of error is given by this formula:

ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}    (a)

And on this case we have that ME =4 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

n=(\frac{z_{\alpha/2} \sigma}{ME})^2   (b)

The critical value for 96% of confidence interval now can be founded using the normal distribution. The significance is \alpha=1-0.96 =0.04. And in excel we can use this formula to find it:"=-NORM.INV(0.02;0;1)", and we got z_{\alpha/2}=2.054, replacing into formula (b) we got:

n=(\frac{2.054(12)}{4})^2 =37.97 \approx 38

So then the minimum sample to ensure the condition given is n= 38

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