Question

FIND Y IN XYZ, help please

Answer 1

Given:

In triangle $XYZ,m\angle X=90^\circ, m\angle Y=45^\circ, m\angle Z=45^\circ, XZ=y,YZ=15\sqrt{2}$.

To find:

The value of y.

Solution:

In a right angle triangle,

$\sin \theta =\dfrac{Perpendicular}{Hypotenuse}$

Using the above ratio for the triangle XYZ, we get

$\sin Y =\dfrac{XZ}{YZ}$

$\sin 45^\circ =\dfrac{y}{15\sqrt{2}}$

$\dfrac{1}{\sqrt{2}}=\dfrac{y}{15\sqrt{2}}$

$\dfrac{15\sqrt{2}}{\sqrt{2}}=y$

$15=y$

Therefore, the correct option is C.