6x10 to the power of zero
2 answers:
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Answer:
The solution of the given initial value problems in explicit form is and the solutions are defined for all real numbers.
Step-by-step explanation:
The given differential equation is
It can be written as
Use variable separable method to solve this differential equation.
Integrate both the sides.
... (1)
It is given that y(1) = -2. Substitute x=1 and y=-2 to find the value of C.
The value of C is -2. Substitute C=-2 in equation (1).
Therefore the solution of the given initial value problems in explicit form is .
The solution is quadratic function, so it is defined for all real values.
Therefore the solutions are defined for all real numbers.
Answer:
For , the group is CLOSED as it a polynomial.
Step-by-step explanation:
Here, the given polynomials are:
Now, a group G is said to be <u>CLOSED UNDER SUBTRACTION</u> if,
a and b are he elements of G ⇒ (a-b) is ALSO AN ELEMENT of G
Now, here:
or,
Also, R(x) is a POLYNOMIAL.
So, R(x) is an Element of group G.
So, the set G of polynomials.
Hence, for the polynomial , it will be a polynomial the group is CLOSED.