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2 years ago

If you were travelling outward from the earth in a space shuttle at an altitude of 88.4 km you would be in the ----------

Chemistry

2 answers:

Alinara [238K]2 years ago

6 0

Answer:air

Explanation:

Nadusha1986 [10]2 years ago

6 0

Answer:

air

Explanation:

you would be going through air

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Alkali Metals are Group 1 so

Rb it isnt Hydrogen because it is a gas

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2 years ago

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What is called exothermic

Jobisdone [24]

An exothermic process is one that gives off heat.

Explanation:

This heat is transferred to the surroundings. An endothermic process is one in which heat has to be supplied to the system from the surroundings.

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2 years ago

A scientist finds an unusual object and decides to study it. Which observation indicates that the object is a living thing?

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3 years ago

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Is 2Zn + 2HCI = ZnCL2 + H2 balanced or unbalanced

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3 years ago

The Ka for formic acid (HCO2H) is 1.8 × 10-4. What is the pH of a 0.35 M aqueous solution of sodium formate (NaHCO2)?

anzhelika [568]

Answer:

9.36

Explanation:

Sodium formate is the conjugate base of formic acid.

Also,

$K_a\times K_b=K_w$

$K_b$ for sodium formate is $K_b=\frac {K_w}{K_a}$

Given that:

$K_a$ of formic acid = $1.8\times 10^{-4}$

And, $K_w=10^{-14}$

So,

$K_b=\frac {10^{-14}}{1.8\times 10^{-4}}$

$K_b=5.5556\times 10^{-11}$

Concentration = 0.35 M

HCOONa ⇒ Na⁺ + HCOO⁻

Consider the ICE take for the formate ion as:

HCOO⁻ + H₂O ⇄ HCOOH + OH⁻

At t=0 0.35 - -

At t =equilibrium (0.35-x) x x

The expression for dissociation constant of sodium formate is:

$K_{b}=\frac {[OH^-][HCOOH]}{[HCOO^-]}$

$5.5556\times 10^{-11}=\frac {x^2}{0.35-x}$

Solving for x, we get:

x = 0.44×10⁻⁵ M

pOH = -log[OH⁻] = -log(0.44×10⁻⁵) = 4.64

pH + pOH = 14

So,

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3 years ago