Answer:
c. carbon monoxide
Explanation:
no one bothers to read why anyways so look at the picture
Protons Ha and Hb in the compound given are enantiotopic.
<h3>What are enantiotopic protons?</h3>
Enantiotopic protons can be defined as those protons that can be replaced by another groups like deuterium.
<h3>What is a compound?</h3>
A compound is a substance which contains two or more elements chemically combined together.
So therefore, Protons Ha and Hb in the compound given are enantiotopic.
Learn more about enantiotopic protons:
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Answer: Equilibrium constant for this reaction is 
.
Explanation:
Chemical reaction equation for the formation of nickel cyanide complex is as follows.
 + 2OH^{-}(aq)](https://tex.z-dn.net/?f=Ni%28OH%29_%7B2%7D%28s%29%20%2B%204CN%5E%7B-%7D%28aq%29%20%5Crightleftharpoons%20%5BNi%28CN%29_%7B4%7D%5E%7B2-%7D%5D%28aq%29%20%2B%202OH%5E%7B-%7D%28aq%29)
We know that,
K = 
We are given that, 
and, 
Hence, we will calculate the value of K as follows.
K =
K = 
=
Thus, we can conclude that equilibrium constant for this reaction is .
Answer:
Density: The molecules of a liquid are packed relatively close together. Consequently, liquids are much denser than gases. The density of a liquid is typically about the same as the density of the solid state of the substance.
In a gas, the distance between molecules, whether monatomic or polyatomic, is very large compared with the size of the molecules; thus gases have a low density and are highly compressible. In contrast, the molecules in liquids are very close together, with essentially no empty space between them
I hope it helps you
Answer:
Average atomic mass = 51.9963 amu
Explanation:
Given data:
Abundance of Cr⁵⁰ with atomic mass= 4.34%
, 49.9460 amu
Abundance of Cr⁵² with atomic mass = 83.79%, 51.9405 amu
Abundance of Cr⁵³ with atomic mass =9.50%, 52.9407 amu
Abundance of Cr⁵⁴ with atomic mass = 2.37%, 53.9389 amu
Average atomic mass = 51.9963 amu
Solution:
Average atomic mass = (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass +....n) / 100
Average atomic mass = (4.34×49.9460)+(83.79×51.9405) +(9.50×52.9407)+ (2.37×53.9389) / 100
Average atomic mass = 216.7656 + 4352.0945 + 502.9367 +127.8352 / 100
Average atomic mass = 5199.632 / 100
Average atomic mass = 51.9963 amu
