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zavuch27 [327]
3 years ago
14

How many moles are there in 7.24 grams of calcium carbonate? With work shown

Chemistry
2 answers:
balu736 [363]3 years ago
8 0

Answer:

0.0723371390261859

slava [35]3 years ago
5 0
CaCO3 = 40 + 12 + 16*3 = 100 g/mol
Mol CaCO3 = m/M = 7.24/ 100 = 0.0724 mol
Can you mark it brainliest?
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Write a net ionic equation to show how isoquinoline, c9h7n, behaves as a base in water.
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There can be three definitions of a base: Arrhenius base, Lewis base or Bronsted-Lowry base. Isoquinoline acts specifically as a Bronsted-Lowry base, which is a proton acceptor. Also, it acts as an Arrhenius base because it produces OH- ions after the reaction. The net ionic equation is:

<span><em>C</em></span><em>₉</em><span><em>H</em></span><em>₇</em><span><em>N (aq) + H</em></span><em>₂</em><span><em>O ---> C</em></span><em>₉</em><span><em>H</em></span><em>₇</em><span><em>NH</em></span><em>⁺</em><span><em> (aq) + OH</em></span><em>⁻</em><span><em> (aq)</em></span>
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3 years ago
If you add 14.22ml of 2.97m hcl (42.2mmol) to an antacid, then neutralize the excess acid with 5.00ml of 0.1055 m naoh (0.528mmo
Vinvika [58]

Given data:

Volume of HCl = 14.22 ml

Molarity of HCl = 2.97 M

mmoles of HCl = 14.22 * 2.97 = 42.2 mmoles

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mmoles of NaOH = 5.00 *.1055 = 0.5275 mmoles

Since HCl and NaOH combine in a 1:1 ratio

# moles of NaOH = # moles of excess HCl that is neutralized = 0.5275 moles

Now, the total moles of HCl taken = # mmoles HCl neutralized by antacid + # mmoles of excess HCl

42.2 = mmoles HCl neutralized by antacid + 0.5275

Therefore,

mmoles of HCl neutralized by antacid = 42.2 - 0.5275 = 41.6725 mmoles = 41.7 mmoles


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Explanation:

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It would (probably) be:
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Explanation:

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