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Fofino [41]
4 years ago
15

What are the relationships between wavelength, wavenumber and frequency with energy? *

Chemistry
1 answer:
wariber [46]4 years ago
4 0

Answer:

E=hcλ or E=hν , where h is Planck's constant i.e, energy is directly proportional to frequency and inversely proportional to wavelength.

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At 570. mm Hg and 25°C, a gas sample ne (in mm Hg) at a volume of 1250 mL and a temperature of 175°C and 25°C, a gas sample has
maw [93]

Answer:

final pressure ( P2) = 467.37 mm Hg

Explanation:

ideal gas:

  • PV = nRT

∴ P1 = 570 mm Hg * ( atm / 760 mm Hg ) = 0.75 atm

∴ T1 = 25 ° C = 298 K

∴ V1 = 1.250 L

∴ R = 0.082 atm L / K mol

⇒ n = P1*V1 / R*T1

⇒ n = (( 0.75 ) * ( 1.25 )) / (( 0.082 ) * ( 298 ))

⇒ n = 0.038 mol gas

∴ T2 = 175 °C ( 448 K )

∴ V2 = 2.270 L

⇒ P2 = nRT2 / V2

⇒ P2 = (( 0.038 ) * ( 0.082 ) * ( 448 )) / 2.270

⇒ P2 = 0.615 atm * ( 760 mm Hg / atm ) = 467.37 mm Hg

5 0
3 years ago
Which particle model diagram represents xenon at stp?
Readme [11.4K]

The model that should show the corresct representation of xenon gas is one in which the gas molecules  are isolated and monoatomic.

<h3>What is a noble gas?</h3>

A noble gas is a member of group 18 of the periodic table. Noble gases are known not to interact with each other and occur as monoatomic particles.

The images are not shown here hence the question is incomplete. However, we do know that any of the models that show individual monoatomic particles is a representation of xenon gas.

Learn more about noble gas: brainly.com/question/2094768

3 0
2 years ago
The Ka for formic acid (HCO2H) is 1.8 × 10-4. What is the pH of a 0.35 M aqueous solution of sodium formate (NaHCO2)?
anzhelika [568]

Answer:

9.36

Explanation:

Sodium formate is the conjugate base of formic acid.

Also,

K_a\times K_b=K_w

K_b for sodium formate is K_b=\frac {K_w}{K_a}

Given that:

K_a of formic acid = 1.8\times 10^{-4}

And, K_w=10^{-14}

So,

K_b=\frac {10^{-14}}{1.8\times 10^{-4}}

K_b=5.5556\times 10^{-11}

Concentration = 0.35 M

HCOONa    ⇒     Na⁺ +    HCOO⁻

Consider the ICE take for the formate  ion as:

                                   HCOO⁻ + H₂O   ⇄   HCOOH + OH⁻

At t=0                              0.35                            -              -

At t =equilibrium           (0.35-x)                          x           x            

The expression for dissociation constant of sodium formate is:

K_{b}=\frac {[OH^-][HCOOH]}{[HCOO^-]}

5.5556\times 10^{-11}=\frac {x^2}{0.35-x}

Solving for x, we get:

x = 0.44×10⁻⁵  M

pOH = -log[OH⁻] = -log(0.44×10⁻⁵) = 4.64

pH + pOH = 14

So,

<u>pH = 14 - 4.64 = 9.36</u>

5 0
3 years ago
How many moles are contained in 2.0 L of N2 at standard temperature and pressure.
GuDViN [60]

0.091 moles are contained in 2.0 L of N2 at standard temperature and pressure.

Explanation:

Data given:

volume of the nitrogen gas = 2 litres

Standard temperature = 273 K

Standard pressure = 1 atm

number of moles =?

R (gas constant) = 0.08201 L atm/mole K

Assuming nitrogen to be an ideal gas at STP, we will use Ideal Gas law

PV = nRT

rearranging the  equation to calculate number of moles:

PV = nRT

n = \frac{PV}{RT}

putting the values in the equation:

n = \frac{1X2}{0.08201 X 273}

n = 0.091 moles

0.091 moles of nitrogen gas is contained in a container at STP.

6 0
3 years ago
A 0.10 M solution of Na2HPO4 could be made a buffer solution with all of the following EXCEPT ________.NaH2PO4K3PO4Na3PO4H3PO4
Kipish [7]

The answer is: H₃PO₄.

A phosphoric acid is three protic acid, which means that in water release tree protons.

Phosphoric acid ionizes in three steps in water.

First step: H₃PO₄(aq) ⇄ H₂PO₄⁻(aq) + H⁺(aq).

Second step: H₂PO₄⁻(aq)⇄ HPO₄²⁻(aq) + H⁺(aq).

Third step: HPO₄²⁻(aq) ⇄ PO₄³⁻(aq) + H⁺(aq).

Species that are present: H₃PO₄, H₂PO₄⁻, HPO₄²⁻, PO₄³⁻ and H⁺.

A buffer can be defined as a substance that prevents the pH of a solution from changing by either releasing or absorbing H⁺ in a solution.

Buffer is a solution that can resist pH change upon the addition of an acidic or basic components and it is able to neutralize small amounts of added acid or base, pH of the solution is relatively stable.

7 0
3 years ago
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