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Fofino [41]
4 years ago
15

What are the relationships between wavelength, wavenumber and frequency with energy? *

Chemistry
1 answer:
wariber [46]4 years ago
4 0

Answer:

E=hcλ or E=hν , where h is Planck's constant i.e, energy is directly proportional to frequency and inversely proportional to wavelength.

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The combustion of caffeine with the molecular masses is given below. If you have 0.150 grams of caffeine, how much NO2 in grams
lord [1]

Answer:

1. 0.14 g of NO2.

2. 0.27 g of CO2.

Explanation:

The balanced equation for the reaction is given below:

2C8H10N4O2 + 27O2 —> 16CO2 + 10H2O + 8NO2

Next, we shall determine the mass of caffeine, C8H10N4O2 that reacted and the masses of nitrogen (iv) oxide, NO2 and carbon (iv) oxide, CO2 produced from the balanced equation. This can be obtained as follow:

Molar mass of of C8H10N4O2 = 194.19 g/mol

Mass of C8H10N4O2 from the balanced equation = 2 × 194.19 = 388.38 g

Molar mass of CO2 = 44.01 g/mol

Mass of CO2 from the balanced equation = 16 × 44.01 = 704.16 g

Molar mass of NO2 = 46.01 g/mol

Mass of NO2 from the balanced equation = 8 × 46.01 = 368.08 g

Summary:

From the balanced equation above,

388.38 g of caffeine, C8H10N4O2 reacted to produce 704.16 g of CO2 and 368.08 g of NO2.

1. Determination of the mass of NO2 produced from the reaction.

This can be obtained as follow:

From the balanced equation above,

388.38 g of caffeine, C8H10N4O2 reacted to produce 368.08 g of NO2.

Therefore, 0.15 g of caffeine, C8H10N4O2, will react to produce = (0.15 × 368.08) / 388.38 = 0.14 g of NO2.

Therefore, 0.14 g of NO2 was obtained from the reaction.

2. Determination of the mass of CO2 produced from the reaction.

This can be obtained as follow:

From the balanced equation above,

388.38 g of caffeine, C8H10N4O2 reacted to produce 704.16 g of CO2.

Therefore, 0.15 g of caffeine, C8H10N4O2, will react to produce = (0.15 × 704.16) / 388.38 = 0.27 g of CO2.

Therefore, 0.27 g of CO2 was obtained from the reaction.

8 0
3 years ago
Which statement describes how the Van Allen belts are formed? O when low-energy particles from the Sun bounce off Earth’s magnet
aniked [119]

Answer:

when high-energy particles from the sun are trapped by earth's magnetic field

Explanation:

it is produced by a "depression" in the Earth's magnetic field in that area, caused by the fact that the center of the Earth's magnetic field is deviated from its geographic center by 450 km. Such an anomaly is thought by some to be a side effect of a Geomagnetic Reversal. These radiation belts originate from the Earth's intense magnetic field that is the product of their rotation. That field traps charged particles (plasma) from the Sun (solar wind), as well as charged particles that are generated by interaction of the Earth's atmosphere with cosmic radiation and high-energy solar radiation.

8 0
3 years ago
Read 2 more answers
Write the net ionic equation:. . A solution of diamminesilver(I) chloride is treated with dilute nitric acid
zimovet [89]
<span> Ag(NH3)2Cl + 3HNO3 = AgNO3 +2NH4NO3 + HCl </span>
<span>or
 Ag(NH3)2Cl + HNO3 = Ag(NH3)2NO3 + HCl  this the complete balanced equation
now remove spectator ions to get net ionic equation
so 
</span>
<span> 2H+ + 2NO3- + [Ag(NH3)2]+ Cl- -> AgCl + 2NH4+ + 2NO3-  2NO3-  2H+  [Ag(NH3)2]+ + Cl- -> AgCl + 2NH4+
</span>hope it helps
5 0
3 years ago
Read 2 more answers
A galvanic cell is powered by the following redox reaction: Br2 H2 2OH Answer the following questions about this cell. If you ne
Hoochie [10]

Answer:

1.91 V

Explanation:

The correct cell reaction. equation is;

Br2(l) + H2(g) + 2OH-(aq) -> 2Br-(aq) + 2H2O(l)

Anode half reaction;

H2(g) + 2OH^-(aq) --------> 2H2O(l) +2e- -0.82 V

Cathode half reaction;

Br2(l) + 2e- -----> 2Br^-(aq). +1.09 V

Hence

E° cell= E°cathode - E°anode

E° cell= 1.09 - (-0.82)

E° cell= 1.91 V

8 0
4 years ago
an unknown sample required 21.05 mL of 0.02047 M KmnO4 to reach the end point. How many moles of KmnO4 reacted?
Angelina_Jolie [31]
.02047 = x / 0.02105 = 0.0004309mol
6 0
4 years ago
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