I have no clue what you are talking about I am so sorry
It would bbe d because content is what is in something
import java.util.Scanner;
public class JavaApplication58 {
public static void main(String[] args) {
Scanner scan = new Scanner(System.in);
System.out.println("Enter a positive integer:");
String num = scan.nextLine();
for (int i = num.length()-1; i >=0; i--){
System.out.println(num.charAt(i));
}
}
}
I hope this helps!
Answer:
B. 1 6 3
Explanation:
Given function definition for calc:
void calc (int a, int& b)
{
int c;
c = a + 2;
a = a * 3;
b = c + a;
}
Function invocation:
x = 1;
y = 2;
z = 3;
calc(x, y);
cout << x << " " << y << " " << z << endl;
- Since x is passed by value, its value remains 1.
- y is passed by reference to the function calc(x,y);
Tracing the function execution:
c=3
a=3
b=c+a = 6;
But b actually corresponds to y. So y=6 after function call.
- Since z is not involved in function call, its value remain 3.
So output: 1 6 3
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