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kramer
3 years ago
8

How many sulfur atoms are there in 4.45 mol of sulfur?

Chemistry
1 answer:
tatiyna3 years ago
4 0
My solving is a bit messy tho....HOPE I HELPED

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Please help! I'm struggling!​
natita [175]

the answer is 1 or A

8 0
3 years ago
A cup holding 125.12g of water has an initial temperature of 26.8 degrees C. After a 35.08g piece of metal, at 99.5 degrees C, i
nignag [31]
<h3>Answer:</h3>

0.620 J/g°C

<h3>Explanation:</h3>

Heat gained or absorbed, Q by a substance is calculated by;

Q = mass × specific heat capacity × Change in temperature

In this case we are given;

  • Mass of water = 125.12 g
  • Initial temperature of water = 26.8 °C
  • Initial temperature of the metal = 99.5°C
  • Final temperature of the mixture = 29.7 °C

We are required to calculate the specific heat capacity of the metal;

<h3>Step 1 : Heat absorbed by water </h3>

Specific heat capacity of water = 4.184 J/g°C

Temperature change of water = 29.7 °C - 26.8°C

                                                   = 2.9 °C

But, Q = m×c×ΔT

Thus, Heat = 125.12 g × 2.9°C × 4.184 J/g°C

                  = 1518.156 Joules

<h3>Step 2; Heat lost by the metal </h3>

Specific heat capacity of the metal = x J/g°C

Temperature change of the metal = 29.7 °C - 99.5°C

                                                         = -69.8 °C

But, Q = mcΔT

Therefore;

Heat lost by the meatl = 35.08 g × x J/g°C × 69.8 °C

                                     = 2.448.584x Joules

<h3>Step 3: C;aculating the specific heat capacity of the metal </h3>

The heat gained by water is equal to the heat lost by the metal

Therefore;

1518.156 Joules = 2.448.584x Joules

x = 1518.156 J ÷ 2.448.584 J

   = 0.620 J/g°C

Therefore, the specific heat of the metal is 0.620 J/g°C

8 0
4 years ago
Nucleotide bases bonded to a sugar phosphate backbone make up _____.
Alchen [17]
Nucleotide bases bonded to a sugar phosphate backbone make up nucleic acids such as DNA (deoxyribonucleic acid) and RNA (<span>ribonucleic acid)</span>. Nucleotides have three major parts: sugars, phosphates, and a nitrogenous base. DNA uses four nitrogenous bases: Adenine, Guanine, Cytosine, and Thymine. RNA uses the same bases except for Thymine, which is replaced by Uracil.
5 0
4 years ago
The volume of a gas held at constant temperature varies indirectly as the pressure of the gas. If the volume of a gas is 1200 cu
kvasek [131]

Answer:

Volume of the gas at 500 mm Hg pressure is 960 cm^{3}

Explanation:

Let's assume the gas behaves ideally.

According to combined gas law for an ideal gas-

                  \frac{P_{1}V_{1}}{T_{1}}=\frac{P_{2}V_{2}}{T_{2}}

Where P_{1} and  P_{2} are initial and final pressure of the gas respectively.  V_{1} and  V_{2} are initial and final volume of the gas respectively.  T_{1} and  T_{2} are initial and final temperature of the gas in kelvin respectively.

Here T_{1} = T_{2}, V_{1} = 1200 cm^{3}, P_{1} = 400 mm Hg, P_{2} = 500 mm Hg

So, V_{2}=\frac{P_{1}V_{1}T_{2}}{T_{1}P_{2}}

Hence V_{2}=\frac{400\times 1200}{500}[tex]cm^{3}=960 cm^{3}[/tex]

Hence volume of the gas at 500 mm Hg pressure is 960 cm^{3}

3 0
4 years ago
Can anyone explain how to do this?
Roman55 [17]

Answer:

hello u need help? 9i0

Explanation:

3 0
3 years ago
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