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kramer
3 years ago
8

How many sulfur atoms are there in 4.45 mol of sulfur?

Chemistry
1 answer:
tatiyna3 years ago
4 0
My solving is a bit messy tho....HOPE I HELPED

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Chuck wants to know how many electrons in an atom are not paired up. Which model would be best for Chuck to
loris [4]

Answer:

D. an orbital notation of the atom

Explanation:

Orbital notiation uses lines and arrows to show shells, subshells, and orbitals for electrons in an atom. Since it shows arrows being paired up in this diagram it would be the best model for Chuck to use.

4 0
3 years ago
Please help me thanks
Digiron [165]

Answer:

your finger becomes negatively charged

Explanation:

5 0
3 years ago
Read 2 more answers
What’s the temperature at the boiling and freezing point of water in fanrenheit
Dominik [7]

Answer:

Boiling is 212* Freezing is 32*

Explanation:

It simple facts

5 0
3 years ago
What volume of Co2 (carbon (iv) oxide)
hram777 [196]

Answer:

2.1056L or 2105.6mL

Explanation:

We'll begin by calculating the number of mole in 10g of Na2CO3. This can be obtained as follow:

Molar mass of Na2CO3 = (23x2) + 12 + (16x3) = 106g/mol

Mass of Na2CO3 = 10g

Mole of Na2CO3 =.?

Mole = mass /molar mass

Mole of Na2CO3 = 10/106

Mole of Na2CO3 = 0.094 mole

Next, we shall determine the number of mole CO2 produced by the reaction of 0.094 mole of Na2CO3. This is illustrated below:

Na2CO3 + 2HCl —> 2NaCl + H2O + CO2

From the balanced equation above,

1 mole of Na2CO3 reacted to produce 1 mole of CO2.

Therefore, 0.094 mole of Na2CO3 will also react to 0.094 mole of CO2.

Next, we shall determine the volume occupied by 0.094 mole of CO2 at STP. This is illustrated below:

1 mole of a gas occupy 22.4L at STP. This implies that 1 mole CO2 occupies 22.4L at STP.

Now, if 1 mole of CO2 occupy 22.4L at STP, then, 0.094 mole of CO2 will occupy = 0.094 x 22.4 = 2.1056L

Therefore, the volume of CO2 produced is 2.1056L or 2105.6mL

7 0
3 years ago
HELP NOW BRAINLIST AND 15 POINTS!!!!! I'M TIMIED!!!!!
goblinko [34]

Answer:

Explanation:

1 =  The given chemical reaction does not follow the law of conservation of mass because,

2 = Four hydrogen atoms are present in reactant side and two hydrogen atoms are present in product side.

3 = 1 ) The given chemical reaction does not follow the law of conservation of mass because,

CH₄ + O₂     →    CO₂  + H₂O

16 g  + 32 g       44 g  +  18 g

 48 g                        62 g

Law of conservation of mass:

This law stated that mass can not be created or destroyed in chemical reaction. It just changed from one to another form.

For example:

C₂H₄   +   3O₂   →    2CO₂   +  2H₂O

28 g   + 96 g    =      88 g  +  36 g

   124  g           =      124 g

6 0
3 years ago
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