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nordsb [41]
3 years ago
11

How many liters of C3H6O are present in a sample weighing 25.6 grams?

Chemistry
1 answer:
lawyer [7]3 years ago
4 0

To Find :

Number of moles of C₃H₆O present in a sample weighing 25.6 grams.

Solution :

Molecular mass of C₃H₆O is :

M = (6×12) + (6×1) + (16×1) grams

M = 94 grams/mol

We know, number of moles of 25.6 grams of C₃H₆O is :

n = \dfrac{Given \ Mass \ Of \ C_3H_6O }{Molar\ Mass \ Of \ C_3H_6O }\\\\n = \dfrac{25.6}{94}\ mole\\\\n = 0.27 \ mole

Hence, this is the required solution.

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1. How many sublevels are in the following principal energy levels?
mafiozo [28]

Explanation:

a 1 ( only "s"

b 2 ( "s" ,"p" )

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6 0
4 years ago
4. How many moles are in 9.12 x 1023 molecules of sugar? And I want the steps to so that I can understand better
Aleksandr-060686 [28]

Answer:

Step 1: List the known quantities and plan the problem.

Known

number of C atoms = 4.72 × 10 24

1 mole = 6.02 × 10 23 atoms

Unknown

4.72 × 10 24 = ? mol C

One conversion factor will allow us to convert from the number of C atoms to moles of C atoms.

Step 2: Calculate.

 

4.72 times 10^{24} text{atoms C} times frac{1  text{mol C}}{6.02 times 10^{23} text{atoms C}}=7.84  text{mol C}

Step 3: Think about your result.

The given number of carbon atoms was greater than Avogadro’s number, so the number of moles of C atoms is greater than 1 mole.  Since Avogadro’s number is a measured quantity with three significant figures, the result of the calculation is rounded to three significant figures.

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7 0
3 years ago
Problem Page Question A major component of gasoline is octane C8H18. When liquid octane is burned in air it reacts with oxygen O
KATRIN_1 [288]

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For this we must first look at the reaction taking place:

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2(C8H18)+25(O2) --> 18(H2O) + 16(CO2)

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2.4molH2O ((2mol of C8H18)/(18mol of H2O)) = 0.3mol C8H18

3 0
3 years ago
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