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2 years ago

so like what if i go in my garage and start my car and rev the engine with all doors closed what would happen

Chemistry

2 answers:

yKpoI14uk [10]2 years ago

6 0

Answer:

At very low RPM the engine suffers from excessive effort, such as accelerating hard in 5th at 1,500 RPM, and by the same rule of thumb, running the engine unjustifiably reduces the effectiveness of the lubrication and increases consumption.

Alex787 [66]2 years ago

4 0

Answer: You would have the worst experience ever

Explanation: Don’t try it.

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Listed below are sets of elements.

Anna11 [10]

The correct answer is B) Chlorine, Sulfur, and Silicon

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3 years ago

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A certain compound is made up of one phosphorus (P) atom, three chlorine (Cl) atoms, and one oxygen (O) atom. What is the chemic

Karolina [17]

POCl3 is the chemical formula of compound.

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3 years ago

Need help with the balancing one

DochEvi [55]

The third option, 2,2,1,2

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3 years ago

Enough of a monoprotic weak acid is dissolved in water to produce a 0.0172 M solution. If the pH of the resulting solution is 2.

Mumz [18]

Answer:

9.7 x 10⁻⁴

Explanation:

HA ⇄ H⁺ + A⁻

C(eq) 0.0174 10⁻²·³⁹ 10⁻²·³⁹

=0.0041M =0.0041M

Ka = [H⁺][A⁻]/[HA] = (0.0014)²/(0.0174) = 9.7 x 10⁻⁴

8 0

3 years ago

A certain amount of H2S was added to a 2.0 L flask and allowed to come to equilibrium. At equilibrium, 0.072 mol of H2 was found

SIZIF [17.4K]

Answer:

0.098 moles H₂S

Explanation:

The reaction that takes place is

2H₂(g) + S₂(g) ⇄ 2H₂S(g) keq = 7.5

We can express the equilibrium constant as:

keq = [H₂S]² / [S₂] [H₂]² = 7.5

With the volume we can calculate the equilibrium concentration of H₂:

[H₂] = 0.072 mol / 2.0 L = 0.036 M

The stoichiometric ratio tells us that the concentration of S₂ is half of the concentration of H₂:

[S₂] = [H₂] / 2 = 0.036 M / 2 = 0.018 M

Now we can calculate [H₂S]:

7.5 = [H₂S]² / (0.018*0.036²)

[H₂S] = 0.013 M

So 0.013 M is the concentration of H₂S at equilibrium.

This would amount to (0.013 M * 2.0 L) 0.026 moles of H₂S

The moles of H₂ at equilibrium are equal to the moles of H₂S that reacted.

Initial moles of H₂S - Moles of H₂S that reacted into H₂ = Moles of H₂S at equilibrium

Initial moles of H₂S - 0.072 mol = 0.026 mol

Initial moles of H₂S = 0.098 moles H₂S

8 0

3 years ago