Answer:
Orbitals
Shells
Energy Levels
Explanation:
Elements in the same period will have the same energy levels which is the same as orbitals and shells.
- The period of an element indicates the energy level in an atom.
- Elements in period 1 will have one energy level or shell or orbitals.
- Down a group this is not the case.
- The energy level increases from top to bottom.
- As we go down the group, we are transiting from one period to another.
Answer :
Charles's Law : It is defined as the volume is directly proportional to the temperature of the gas at constant pressure and number of moles.
Mathematically,

Boiling water bath Cool bath 1 Cool bath 2
Temperature (⁰C) 99 17 2
Temperature (K)(T) 273+99=372 273+17=290 273+2=275
Volume of water 0.0 27.0 34.0
in cool flask (mL)
Volume of water= 135.8 135.8 135.8
Air in flask (mL)
Volume of air 135.8 108.8 101.8
in cool flask (V)

The graph volume versus temperature for a gas is shown below.
Answer:

Explanation:
First you should calculate the volume of a big sphere,so:



Then you calculate the volume of a small spehre, so:



Finally you subtract the two quantities:


Answer:
Heat required = 13,325 calories or 55.75 KJ.
Explanation:
To convert a water to steam at 100 degree celsius to vapor, we have to give latent heat of vaporization to water
Which equals ,
Q = mL,
Where, m is the mass of water present
L = specific latent heat of vaporization
Here , m= 25 gram
L equals to 533 calories (or 2230 Joules)
So, Q = 25×533 = 13,325 Calories
Or , Q = 55,750 Joules = 55.75 KJ
so, Heat required = 13,325 calories or 55.75 KJ.