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3 years ago

9

Translate the sentence into an inequality. The sum of a number times 4 and 29 is at least 27. Use the variable y for the unknown

number.

1 answer:

Fofino [41]3 years ago

3 0

Answer:

y*4 + 29 >= 27

Step-by-step explanation:

A number times 4 is y*4 and the sum with 29 is y*4 + 29. If this is to be at least 27, it says that y*4 + 29 is greater than or equal to 27.

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How do you integrate 7xe^-5x²?

Nana76 [90]

Making assumptions about where parentheses should be,
<span>Let u = -7x </span>
<span>du = -7dx </span>
<span>dv = e^(2x) dx </span>
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<span>∫ -7xe^(2x) dx = </span>
<span>-7xe^(2x)/2 - ∫ e^(2x)/2 (-7) dx = </span>
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3 years ago

Please help fast!!! Part A How many solutions does the pair of equations for lines A and B have?

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2 years ago

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3 years ago

140/96 into a mixed number

FinnZ [79.3K]

Simplify 140/96 into 35/24 since they have the common factor 4. Then convert it to 1 whole and 11/24

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3 years ago

Read 2 more answers

Could someone help me with this ASAP? thanks !

Maru [420]

<h3>Answer:</h3>

A. $6x^2$ +-5x+14x+-35

$6x^2$ +9x-35

B. $5x^4+-3x^3+10x^3+-6x^2$

$5x^4+7x^3-6x^2$

C. $25x^2+-20x+20x+-16$

$25x^2-16$

D. $x^4+-4x^2+-7x^2+28$

$x^4-11x^2+28$

$====================================$

Step-by-step explanation:

A. (3x*2x)+(3x*-5)+(7*2x)+(7*-5)

Multiply and simplify.

$6x^2$ +9x-35

B. ( $x^2*5x^2$ )+( $x^2*$ -3x)+(2x $*5x^2$ )+(2x $*-3x$ )

Multiply and simplify.

$5x^4+7x^3-6x^2$

C. $(5x*5x)+(5x*-4)+(4*5x)+(4*-4)$

Multiply and simplify.

$25x^2-16$

D. $(x^2*x^2)+(x^2*-4)+(-7*x^2)+(-7*-4)$

Multiply and simplify.

$x^4-11x^2+28$

I hope this helps!

But you should really do this yourself.

3 0

3 years ago