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Neko [114]
2 years ago
12

Calculate the density a rectangular block of a metal whose length is 8.335cm width is 1.02cm height is 0.982cm and mass is 62.35

38gm.
Chemistry
1 answer:
Ostrovityanka [42]2 years ago
8 0

Answer:

Density rectangular block = 7.47 (Approx) gm/cm³

Explanation:

Given:

Length = 8.335 cm

Width = 1.02 cm

Height = 0.982 cm

Mass = 62.3538 gm

Find:

Density rectangular block

Computation:

Volume of block = lbh

Volume of block = (8.335)(1.02)(0.982)

Volume of block = 8.3486 cm³

Density = Mass / Volume

Density rectangular block = 62.3538 / 8.3486

Density rectangular block = 7.47 (Approx) gm/cm³

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H. Nitrogen gas and hydrogen gas combine to produce ammonia gas (NH3).
DedPeter [7]

Answer:

<u>27.3 L</u>

Explanation:

<u>Reaction</u>

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<u>Solving</u>

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4 0
2 years ago
If element x forms the oxides xo and x2o3 the oxidation numbers of element x are
Deffense [45]

Answer:

b) +2 and +3.

Explanation:

Hello,

In this case, given the molecular formulas:

XO

And:

X_2O_3

We can relate the subscripts with the oxidation states by knowing that they are crossed when the compound is formed, for that reason, we notice that oxygen oxidation state should be -2 for both cases and the oxidation state of X in the first formula must be +2 since both X and O has one as their subscript as they were simplified:

X^{+2}O^{-2}

Moreover, for the second case the oxidation state of X should be +3 in order to obtain 3 as the subscript of oxygen:

X_2^{+3}O_3^{-2}

Thus, answer is b)+2 and +3

Best regards.

3 0
2 years ago
I NEED HELP PLEASE, THANKS! :)
saw5 [17]

Answer:

Macroscopic observation

Explanation:

The observation is macroscopic because you could observe the transformation with the naked eye.

3 0
2 years ago
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