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Neko [114]
3 years ago
12

Calculate the density a rectangular block of a metal whose length is 8.335cm width is 1.02cm height is 0.982cm and mass is 62.35

38gm.
Chemistry
1 answer:
Ostrovityanka [42]3 years ago
8 0

Answer:

Density rectangular block = 7.47 (Approx) gm/cm³

Explanation:

Given:

Length = 8.335 cm

Width = 1.02 cm

Height = 0.982 cm

Mass = 62.3538 gm

Find:

Density rectangular block

Computation:

Volume of block = lbh

Volume of block = (8.335)(1.02)(0.982)

Volume of block = 8.3486 cm³

Density = Mass / Volume

Density rectangular block = 62.3538 / 8.3486

Density rectangular block = 7.47 (Approx) gm/cm³

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How many moles of CCI are there in 78.2 g of CCI.?
vaieri [72.5K]

Answer:

0.508 mole

Explanation:

NOTE: Since no hydrogen is attached to the compound given in question above, it means the compound is CCl₄.

The number of mole present in 78.2 g of CCl₄ can be obtained as follow:

Mass of CCl₄ = 78.2 g

Molar mass of CCl₄ = 12 + (35.5×4)

= 12 + 142

= 154 g/mol

Mole of CCl₄ =?

Mole = mass / molar mass

Mole of CCl₄ = 78.2 / 154

Mole of CCl₄ = 0.508 mole

Therefore, 0.508 mole is present in 78.2 g of CCl₄

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