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Anni [7]
3 years ago
12

A 5.0 gram sample of Ag2SO4, will dissolve in 1.0 L of water. Calculate the solubility product

Chemistry
1 answer:
arlik [135]3 years ago
8 0

Answer:

Ksp = 1.64 ×10⁻⁵

Explanation:

Given data:

Mass of  Ag₂SO₄ = 5.0 g

Volume of water = 1.0 L

Solubility product = Ksp = ?

Solution:

First of all we will calculate the molarity.

Molarity = Number of moles of solute / Volume of solution in L

Number of moles = mass/ molar mass

Number of moles = 5.0 g/311.74 g/mol

Number of moles = 0.016 mol

Molarity = 0.016 mol / 1 L

Molarity = 0.016 M

Dissociation equation:

Ag₂SO₄  ⇔  2Ag⁺ + SO₄²⁻

Ksp = [Ag⁺]² [SO₄²⁻]

Ksp = [0.032]²[0.016]

Ksp = 1.64 ×10⁻⁵

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<h3>What is molality?</h3>
  • The number of moles of solute in a solution equal to 1 kg or 1000 g of solvent is referred to as its molality.
  • The definition of molarity, on the other hand, is based on a certain volume of solution.
  • Mol/kg is a typical molality measurement unit in chemistry.
<h3>Calculation of boiling point:</h3>

When the non-volatile solute is dissolved in a solvent, the boiling point rises along with the molality (concentration) of the solute.

Given,

Mass of  C₂H₆O₂ (solute) = 15.0 g

Mass of solvent (H₂O) = 0.50 kg

Molar mass of C₂H₆O₂ = 62 g/mol

Thus, the moles of solute = 15.0 g x 1.0 mol solute/62 g/mol

= 0.2419 mol

Therefore, molality(m) of C₂H₆O₂ (solute) = Amount of solute (mol)/ Mass of solvent

= 0.2419/0.50

= 0.4838 m

Similarly,

Given ,

Mass of  NaCl (solute) = 15 g

Mass of solvent (H₂O) = 0.50 kg

Molar mass of NaCl (solute) = 58.44 g/mol

Thus, the moles of NaCl (solute) = 15.0 g x 1.0 mol solute/58.44

= 0.2566 mol

Therefore, molality(m) of NaCl (solute) = Amount of solute (mol)/ Mass of solvent

= 0.2566 mol/0.50 kg  

= 0.51 m

Hence, the molality of NaCl (solute) is more than the molality of C₂H₆O₂(solute).

So, with an increase in the solute's concentration (molality), the boiling point rises.

Therefore, NaCl has higher boiling point than C₂H₆O₂ in H₂O.

Learn more about boiling point here:

brainly.com/question/24168079

#SPJ4

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