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Elina [12.6K]
3 years ago
13

7. Which of the following physical changes is experienced by women during the luteal stage of the

Chemistry
2 answers:
kenny6666 [7]3 years ago
6 0

Answer:

The correct answer is Choice D.

(Headaches or backaches)​

Explanation:

Hope this helps!

Please mark me as Brainlinieast.

mario62 [17]3 years ago
5 0
The right answer is d
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Chloroform, CHCl3, reacts with chlorine, Cl2, to form carbon tetrachloride, CCl4, and hydrogen chloride, HCl. In an experiment 2
erastovalidia [21]

Answer:

Chloroform= limiting reactant

0.209mol of CCl4 is formed

And 32.186g of CCl4 is formed

Explanation:

The equation of reaction

CHCl3 + Cl2= CCl4 + HCl

From the equation 1 mol of

CHCl3 reacts with 1mol Cl2 to yield 1mol of CCl4

From the question

25g of CHCl3 really with Cl2

Molar mass of CHCl3= 119.5

Molar mass of Cl2 = 71

Hence moles of CHCl3= 25/119.5 = 0.209mol

Moles of Cl2 = 25/71 = 0.352mol

Hence CHCl3 is the limiting reactant

Since 1 mole of CHCl3 gave 1mol of CCl4

It implies that 0.209moles of CHCl3 will also give 0.209mol of CCl4

Mass of CCl4 formed = moles× molar mass= 0.209×154= 32.186g

6 0
3 years ago
What volume of 1.00 m hcl in liters is needed to react completely (with nothing left over) with 0.750 l of 0.100 m na2co3?
kotykmax [81]
The balanced equation for the reaction is as follows
Na₂CO₃ + 2HCl --> 2NaCl + CO₂ + H₂O
stoichiometry of Na₂CO₃ to HCl is 1:2
number of Na₂CO₃ moles reacted = molarity x volume
number of Na₂CO₃ moles = 0.100 mol/L x 0.750 L = 0.0750 mol 
according to molar ratio of 1:2
1 mol of Na₂CO₃ reacts with 2 mol of HCl
then 0.0750 mol of Na₂CO₃ mol reacts with - 2 x 0.0750 = 0.150 mol 
molarity of given HCl solution is 1.00 mol/L
molarity is defined as the number of moles of solute in 1 L of solution 
there are 1.00 mol in 1 L of solution 
therefore there are 0.150 mol in - 0.150 mol / 1.00 mol/L = 0.150 L 
volume of HCl required is 0.150 L 
3 0
3 years ago
A flask with a volume of 125.0mL contains air with a density of 1.269 g/L. What is the mass of the air contained in the flask?
Aliun [14]
<span>In order to solve this problem you must first make sure all your numbers are in like terms. From the density value you can see that it is grams per liter. The first conversion you must do in convert the 125.0 mL value to Liters which you would do by dividing by 1000 because 1 liter is equal to 1000 mL. 125.0 divided by 1000 is 0.125 Liter. Now you will use the density equation to solve. The density equation is density is equal to mass divided by volume. Plug in your known numbers for density and volume. Then solve for mass. So Density (1.269 g/l is equal to mass divided by volume (.125 Liter) You must rearrange the equation to multiple density by volume which is 1.269 times 0.125 which will give you 0.1586. Because the Liters cancel each other out, the answer's unit will be grams. Your final answer is 0.1586 grams.</span>
4 0
3 years ago
How many electrons are needed for cio3-
irinina [24]

Answer:26

Explanation:

5 0
3 years ago
How many moles of O2 are required to react with 6.6 moles of H2?
Bingel [31]

<u>Answer: </u>

<u>For 1:</u> 3.3 moles of oxygen gas is required.

<u>For 2:</u> 14 moles of hydrogen gas is required.

<u>For 3:</u> 1.5 moles of oxygen gas is required.

<u>Explanation:</u>

The chemical reaction of oxygen and hydrogen to form water follows:

O_2+2H_2\rightarrow 2H_2O

  • <u>For 1:</u> When 6.6 moles of H_2 is reacted.

By Stoichiometry of the above reaction:

2 moles of hydrogen gas reacts with 1 mole of oxygen gas.

So, 6.6 moles of hydrogen gas will react with = \frac{1}{2}\times 6.6=3.3mol of oxygen gas.

Hence, 3.3 moles of oxygen gas is required.

  • <u>For 2:</u> When 7.0 moles of O_2 is reacted.

By Stoichiometry of the above reaction:

1 mole of oxygen gas reacts with 2 moles of hydrogen gas.

So, 7 moles of oxygen gas will react with = \frac{2}{1}\times 7=14mol of hydrogen gas.

Hence, 14 moles of hydrogen gas is required.

  • <u>For 3:</u> When 3.0 moles of H_2O is formed.

By Stoichiometry of the above reaction:

2 moles of water is formed from 1 mole of oxygen gas.

So, 3.0 moles of water will be formed from = \frac{1}{2}\times 3.0=1.5mol of oxygen gas.

Hence, 1.5 moles of oxygen gas is required.

7 0
3 years ago
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