Types of Bonds can be predicted by calculating the
difference in electronegativity.
If, Electronegativity difference is,
Less
than 0.4 then it is Non Polar Pure Covalent
Between 0.4 and 1.7 then it is Polar Covalent
Greater than 1.7 then it is Ionic
For Br and Br,
E.N of Bromine = 2.96
E.N of Bromine = 2.96
________
E.N Difference
0.00 (Non Polar/Pure Covalent)
For N and O,
E.N of Oxygen = 3.44
E.N of Nitrogen = 3.04
________
E.N Difference
0.40 (Non Polar/Pure Covalent)
For P and H,
E.N of Hydrogen = 2.20
E.N of Phosphorous = 2.19
________
E.N Difference 0.01 (Non Polar/Pure Covalent)
For K and O,
E.N of Oxygen = 3.44
E.N of Potassium = 0.82
________
E.N Difference 2.62 (Ionic)
Must be Selenium (Se). It is two space away from Kr, which means that it needs two extra electron to be like a noble gas, Kr.
Answer:
What was the assignment? There's nothing attached, my guy
Explanation:
Answer:
<em> three stereoisomers
</em>
<em>Hence there are only three stereoisomers of 1,2-dichlorocyclopentane.</em>
<em />
Explanation:
1. 2NaN3 —> 2Na + 3N2
2. 2Pb + 2H2O + O2 —> 2Pb(OH)2
3. 2C4H12 + 13O2 —> 8CO2 + 10H2O
4. 4Fe + 3Sn(NO3)4 —> 4Fe(NO3)3 + 3Sn
5. Fe(NO3)3 + 3NaOH —> Fe(OH)3 + 3NaNO3
Balancing equations depends on the atom numbers you start with.
If you are having trouble you can look up ‘chemical equation balancer’ and type in the starting elements and simply replace the arrow with an = equal sign and then enter the reactants. It will show you the balanced equation
But please— make sure you actually understand the process of balancing because it’s important for future chem classes
