A student is observing different structures of a seed plant during a lab activity. She has identified tiny structures that look
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Explanation:
The given data is as follows.
Vapour pressure of pure = 33.85 Torr
Temperature = 298 K
Mole fraction of = 122.36 torr
Therefore, calculate the vapor pressure of as follows.
Vapour pressure of = mole fraction of
x K of
= 0.050 x 122.36 Torr
= 6.118 Torr
So, vapor pressure of is 6.118 Torr
.
Now, calculate the vapor pressure of carbon tetrachloride as follows.
Vapour pressure of = mole fraction of
x Pressure of
= (1 - 0.050) × 33.85 Torr
= 32.1575 Torr
So, vapor pressure of is 32.1575 Torr .
Hence, the total pressure will be as follows.
= 6.118 Torr + 32.1575 Torr
= 38.2755 Torr
Therefore, composition of =
= 0.8405
Composition of is 0.8405
.
And, composition of =
= 0.1598
Composition of is 0.1598
.