Answer:
The Phosphorylated glucose(glucose +inorganic phosphate), with the energy supplied from ATP hydrolysis formed glucose 6- phosphate, which is later converted to 2 molecules of fructose 6-phosphate- this is phosphorylation.And represented the fate of glucose -6-phosphate.
The fructose 6-phosphate are converted to triose phosphate- which is a 2-molecules of 3C compound. The latter is oxidized by NAD→ NADH+ to form intermediates in the glycolytic pathways .
These intermediates are converted to ribose 5-phosphates in the presence of transketolase and transaldolase enzymes.And they are finally converted to pyruvate in the glycolytic pathway with the production of 2ATPs per molecule of glucose.
Basically the phosphate pathway reaction is very slow due to enzyme catalysis.
Answer:
2.256 moles of oxygen atoms
Explanation:
CaCo3 is calcium carbonate
every mole of calc carb has 3 moles of O atoms
.752 moles of this has 3 times as many moles of Oxygen atoms
having a lesser value by a process of depletion
<h3><u>Condensation of gases into liquids by kinetic molecular theory:</u></h3>
The "kinetic molecular theory" explains the states of matter based on the matter composed of very tiny little particles that are constantly in motion. The theory also explains the observable properties and behaviors of solids, liquids, and gases.
Condensation of particles of a real gas to form liquid is due to the attractive forces present in between them. During the condensation process, gas molecules slows down and come together to form a liquid. And also during the transfer of energy to something cooler, the process slows down and they attract the bond to become liquid. Each particle motion is completely independent. The kinetic energy of gas particles is dependent on the temperature of the gas.
<span>We look at the end of the day:
n(HNO3) added = 0.500*17.0/1000 = 0.00850 mol
n(NH3) = 0.200*75.0/1000 - 0.00850 = 0.00650 mol
[NH3] left = 0.00650*1000/(17.0+75.0) = 0.070652
M [OH-] = Kb * [NH3] = 0.070652*1.8*10^(-5) = 1.27174 x 10^(-6)
pOH = -log[OH-] ≈ 5.8956 pH = 14 - pOH ≈ 8.10</span>
