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PSYCHO15rus [73]
3 years ago
12

A scuba diver 25.0m below the sea surface inhales 75.0mL of compressed air in a scuba tank at a pressure of 3.50atm and a temper

ature of 5.0C. What is the pressure of the air in the lungs if the gas expands to 215.0mL at the body temperature of 37.2C?
Chemistry
1 answer:
julsineya [31]3 years ago
4 0

Answer:

Explanation:

Use the combined gas law

P(V)/T=P(V)/T

P is pressure

V is volume

T is temperature

3.5 atm(75 mL)/(5 C)=P(215 mL)=(37.2 C)

yu can change celcius to kelvin by adding 273.

And then just solve the equation

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325.82 g/mol

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What gas law applies to aerosol cans being stored in a cool place?
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Don't really know if this is what your asking but P1/T1= P2/T2 should show how the pressure varies with temperature (V is left out because it's constant since the gas is trapped in an aerosol can). As the temperature rises the pressure rises and if it gets too high then the can explodes, which is why it should be stored in a cool place. There's also PV=nRT might be kind of hard to find moles (n) though.


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2 years ago
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A 0.04358 g sample of gas occupies 10.0-ml at 292.0 k and 1.10 atm. upon further analysis, the compound is found to be 25.305% c
kirill [66]
<span>Answer: A 0.04403 g sample of gas occupies 10.0-mL at 289.0 K and 1.10 atm. Upon further analysis, the compound is found to be 25.305% C and 74.695% Cl. What is the molecular formula of the compound? --------------------------------------... Seems like I did a problem very similar to this--this must be the "B" test. But the halogen was different. 25.305% C/12 = 2.108 74.695% Cl/35.5 = 2.104 So the empirical formula would be CH. However, there are many compounds which fit this bill, so we have to use the gas data. (And I made, in the previous problem, the simplifying assumption that 289C and 1.10 atm would offset each other, so I'll do that, too.) 0.044 grams/10 ml = x/22.4 liters 0.044g/0.010 liters = x/22.4 liters 22.4 liters/0.010 liters = 2240 (ratio) 2240 x .044 = 98.56 (actual atomic weight) CCl = 35.5+12 or 47.5, so two of those is 95 grams/mole. This is sufficiient to distinguish C2CL2, (dichloroacetylene) from C6CL6 (hexachlorobenzene) which would mass 3 times as much.</span>
3 0
3 years ago
Read 2 more answers
How many moles of gas occupy 98L at a pressure of 2.8atm and a temperature of 292k? and what law would you use?
algol13
Let's assume that the gas has ideal gas behavior.

Then we can use ideal gas equation,
PV = nRT

Where, P is Pressure of the gas (Pa), V is volume of the gas (m³), n is the number of moles of gas (mol), R is the Universal gas constant (8.314 J mol⁻¹ K⁻¹) and T is the temperature in Kelvin (K)

The given data for the gas is,
P = 2.8 atm = 283710 Pa
V = 98 L = 98 x 10⁻³ m³
T = 292 K
R = 8.314 J mol⁻¹ K⁻¹
n = ?

By applying the formula,
283710 Pa x 98 x 10⁻³ m³ = n x 8.314 J mol⁻¹ K⁻¹ x 292 K
                                       n = 11.45 mol

Hence,moles of gas is 11.45 mol.
8 0
3 years ago
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